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Plotting matrix rows with lattice graphics?
4 messages · Ron Bonner, Henrique Dallazuanna, Deepayan Sarkar
Maybe: xyplot(values ~ ind|ind, data = stack(split(m, 1:4)))
On 24/03/2008, Ron Bonner <arbi56 at gmail.com> wrote:
Sorry if this is an FAQ, but I haven't found the answer (yet)... I'm trying to plot each row of a simple numeric matrix in a separate panel using the layout features of lattice, but can't make it work - help would be appreciated! Example:
> m <- matrix(seq(1:20), nrow=4)
> m
[,1] [,2] [,3] [,4] [,5] [1,] 1 5 9 13 17 [2,] 2 6 10 14 18 [3,] 3 7 11 15 19 [4,] 4 8 12 16 20 The following will plot one row in one box:
> xyplot(m[1,] ~ seq(1:5))
but this gives all rows in the same box:
> xyplot(m ~ seq(1:5))
Since there are no factors, how can I set conditioning variable to get
what I want, or is there a better way to do this?
Thanks in advance
Ron
Ron Bonner
arbi56 at gmail.com
skype: rbonners
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Henrique Dallazuanna Curitiba-Paran?-Brasil 25? 25' 40" S 49? 16' 22" O
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On 3/25/08, Ron Bonner <arbi56 at gmail.com> wrote:
Thanks Henrique - that didn't exactly solve my problem but gave me enough to do so! In your solution each row is plotted as a vertical row of points at the value of 'ind' while I wanted to plot the values against the column numbers, i.e. 1 to 5. The solution was to create a vector of column numbers, replicate it and plot against it, still using 'ind' as the conditioning variable:
Also, take a look at ?as.data.frame.table, which should help you create a suitable data frame directly. -Deepayan