3 messages · Dimitri Shvorob, Brad Patrick Schneid, jim holtman
How can one simplify the folowing? t$aum[is.na(t$aum)] = 0; t$aum.core[is.na(t$aum.core)] = 0 t$num[is.na(t$num)] = 0; t$num.core[is.na(t$num.core)] = 0 Thank you.
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look at plyr package colwise (column wise) function
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for (i in c('aum', 'num','aum.core','num.core')) t[[i]][is.na(t[[i]])] <- 0
On Sat, Jan 30, 2010 at 3:34 PM, Dimitri Shvorob
How can one simplify the folowing? t$aum[is.na(t$aum)] = 0; t$aum.core[is.na(t$aum.core)] = 0 t$num[is.na(t$num)] = 0; t$num.core[is.na(t$num.core)] = 0 Thank you. -- View this message in context: http://n4.nabble.com/Applying-a-transformation-to-multiple-data-frame-columns-tp1457641p1457641.html Sent from the R help mailing list archive at Nabble.com.
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Jim Holtman Cincinnati, OH +1 513 646 9390 What is the problem that you are trying to solve?