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Help using smooth.spline with zoo object

3 messages · Rob Denniker, Roger Koenker, Gabor Grothendieck

#
Can someone please show me how to smooth time series data that I have in the form of a zoo object?

I have a monthly economies series and all I really need is to see a less jagged line when I plot it.
 
If I do something like

s <- smooth.spline(d.zoo$Y, spar = 0.2)
plot(predict(s,index(d.zoo)), xlab = "Year")
# not defined for Date objects

and if I do something like

plot(predict(s,as.numeric(index(d.zoo))), xlab = "Year")
# one straight line, no matter the value of spar

What am I doing wrong? (The unsmoothed series plots just fine - a noisy upward trend)

Thanks in advance.

P.S. I would really just like to keep varying the penalty parameter 'lambda' of a Hodrick-Prescott filter until I get a 'smooth enough' series, but an archive search suggests that if I ask for this, some smarty pants will reply saying that the HP filter is just the smooth.spline function applied with a particular choice of lambda and equally spaced observations.

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#
For equally spaced observations this is quite simple and available in   
various packages
but I like Gabor Grothendieck's version  (which didn't come up  
immediately in my Rseek search:

hpfilter  <-  function(y,lambda=1600)
eye <- diag(length(y))
solve(eye+lambda*crossprod(diff(eye,d=2)),y)}

url:    www.econ.uiuc.edu/~roger                Roger Koenker
email   rkoenker at uiuc.edu                       Department of Economics
vox:    217-333-4558                            University of Illinois
fax:    217-244-6678                            Champaign, IL 61820
On Apr 4, 2009, at 2:19 PM, Rob Denniker wrote:

            
#
Try this:

library(zoo)
library(lattice)
z <- as.zoo(EuStockMarkets)
xyplot(z) # original
xyplot(z, type = "smooth") # smooth

In zoo see ?xyplot.zoo and in lattice see ?panel.xyplot
On Sat, Apr 4, 2009 at 3:19 PM, Rob Denniker <bearmarketsrule at inbox.com> wrote: