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grepl

4 messages · Duncan Murdoch, arun, Francesco Isotta

Duncan Murdoch
#
On 13-05-13 4:19 AM, Francesco Isotta wrote:
Use grepl(".", string, fixed=TRUE).


I tried also to insert \. but it
You did not insert \., because you'd need to escape the backslash to do 
that.  grepl("\\.", string) would work.

Duncan Murdoch
arun
# 
You may also try:
grepl("[.]",c("ad.1","ads","ad.2"))
#[1]? TRUE FALSE? TRUE
A.K.



----- Original Message -----
From: Francesco Isotta <isottaf at hotmail.com>
To: r-help at r-project.org
Cc: 
Sent: Monday, May 13, 2013 4:19 AM
Subject: [R] grepl

Hello,
it is not clear to me, how to search if in a string there is a "." (full
stop).
Using:

grepl(".",string)

doesn't work because the full stop it is a metacharacter (it gives "TRUE"
also if no full stop is in the character). I tried also to insert \. but it
does not work.
Error: '\.' is an unrecognized escape in character string starting "\."

Thank you very much for your help

Francesco

??? [[alternative HTML version deleted]]

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