Legend text populated with calculated values and super script?

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Hello,

I am trying to generate a plot legend that contains calculated summary
statistics, one statistic is R^2.  I have tried several variations using
the commands "expression" and "bqoute" as stated on the R help pages.  I
have not been able to get the R^2 super script correct along with the
calculated statistics.

I provided an example below, what I want is the legend (wdt_leg and
spas_leg) as below but with the R^2 as superscript.

# Example Data
x=c(1,2,3,4);  y=c(1,2,3,4); z=c(1.25,1.5,2.5,3.5)

# first stats based on data, used to populate legend
wdt_n = 50;  wdt_mbias = 0.58
wdt_mae = 2.1;  wdt_R2 = 0.85
# second stats based on data, used to populate legend
spas_n = 50; spas_mbias = 0.58
spas_mae = 2.1; spas_R2 = 0.85

# create legend
wdt_leg<- paste("WDT (N = ", wdt_n,", Bias = ",wdt_mbias,", MAE =
",wdt_mae, ", R2 = ", wdt_R2, ")", sep="")
spas_leg<- paste("SPAS (N = ", spas_n,", Bias = ",spas_mbias,", MAE =
",spas_mae, ", R2 = ", spas_R2, ")", sep="")

# create plot
plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)
leg.txt<- c(spas_leg, wdt_leg)
legend("topleft", legend = leg.txt, col=c("red1","green4"), pch=c(1,3),
cex=0.85)

Hi Doug,
I set out to get your legend strings turned into expressions and after 
several tries, gave up. Getting superscripts and subscripts in base 
graphics is fairly easy:

supsubtext<-function(x,y,label,sup=NA,sub=NA,xadj=0.5,...) {
  nlabchar<-nchar(label)
  yadj<-rep(0.5,nlabchar)
  if(!is.na(sup)) yadj[sup]<-0
  if(!is.na(sub)) yadj[sub]<-1
  labbits<-strsplit(label,"")[[1]]
  currentx<-x
  for(labchar in 1:nlabchar) {
   text(x,y,labbits[labchar],adj=c(xadj,yadj[labchar]),...)
   x<-x+strwidth(labbits[labchar])
  }
}

The above function will display a line of text in which any character 
the index of which is in "sup" will be superscripted and any in "sub" 
will be subscripted. It is possible to add "cex" values to reduce the 
size of those characters if necessary. You can then construct a 
serviceable legend manually like this:

plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)
points(c(1,1),c(3.9,3.7),pch=c(1,3),col=c("red1","green4"))
wdt_leg<-"WDT (N = 50, Bias = 0.58, MAE = 2.1, R2 = 0.85)"
spas_leg<-"SPAS (N = 50, Bias = 0.58, MAE = 2.1, R2 = 0.85)"
supsubtext(1.2,3.9,spas_leg,sup=40)
supsubtext(1.2,3.7,wdt_leg,sup=40)
xylim<-par("usr")
segments(c(xylim[1],3.4),c(3.5,3.5),c(3.4,3.4),c(3.5,xylim[4]))

I am sure that someone more expert with expressions will post a more 
elegant solution.

Jim

Hello,

I am trying to generate a plot legend that contains calculated summary 
statistics, one statistic is R^2.  I have tried several variations using 
the commands "expression" and "bqoute" as stated on the R help pages.  I 
have not been able to get the R^2 super script correct along with the 
calculated statistics.

I provided an example below, what I want is the legend (wdt_leg and 
spas_leg) as below but with the R^2 as superscript.

# Example Data
x=c(1,2,3,4);  y=c(1,2,3,4); z=c(1.25,1.5,2.5,3.5)

# first stats based on data, used to populate legend
wdt_n = 50;  wdt_mbias = 0.58
wdt_mae = 2.1;  wdt_R2 = 0.85
# second stats based on data, used to populate legend
spas_n = 50; spas_mbias = 0.58
spas_mae = 2.1; spas_R2 = 0.85

# create legend
wdt_leg <- paste("WDT (N = ", wdt_n,", Bias = ",wdt_mbias,", MAE = 
",wdt_mae, ", R2 = ", wdt_R2, ")", sep="")
spas_leg <- paste("SPAS (N = ", spas_n,", Bias = ",spas_mbias,", MAE = 
",spas_mae, ", R2 = ", spas_R2, ")", sep="")

# create plot
plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)
leg.txt <- c(spas_leg, wdt_leg)
legend("topleft", legend = leg.txt, col=c("red1","green4"), pch=c(1,3), 
cex=0.85)
sublist <- 
structure(list(wdt_n = 50, wdt_mbias = 0.58, wdt_mae = 2.1, wdt_R2 = 0.85, 
    spas_n = 50, spas_mbias = 0.58, spas_mae = 2.1, spas_R2 = 0.85), .Names = c("wdt_n", 
"wdt_mbias", "wdt_mae", "wdt_R2", "spas_n", "spas_mbias", "spas_mae", 
"spas_R2"))

legends <-c( 
  substitute( 
    atop(WDT * group("(", list(N == wdt_n, Bias == wdt_mbias, MAE == wdt_mae ), ")" ),
      R^2 == wdt_R2 ) ,  env=sublist), 
  substitute(   
    atop(SPAS * group("(", list(N == spas_n, Bias == spas_mbias, MAE == spas_mae ), ")"),
      R^2 == spas_R2 ), env=sublist)  )

# I tried with: as.expression( lapply( exprlist, function(e) bquote(e) ) ) but failed repeatedly.
# In order to get `substitute` to cook the bacon, you need to use real expressions, not text.

plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)
legend("topleft", 
   legend = as.expression(legends), 
   col=c("red1","green4"), pch=c(1,3), 
   cex=0.85)
David Winsemius
Alameda, CA, USA
Here's a bquote version:

x=c(1,2,3,4);  y=c(1,2,3,4); z=c(1.25,1.5,2.5,3.5)

# first stats based on data, used to populate legend
wdt_n = 50;  wdt_mbias = 0.58
wdt_mae = 2.1;  wdt_R2 = 0.85
# second stats based on data, used to populate legend
spas_n = 50; spas_mbias = 0.58
spas_mae = 2.1; spas_R2 = 0.85

wleg <- bquote(paste("WDT (", N == .(wdt_n), ", ",
               Bias == .(wdt_mbias), ", ",
               MAE == .(wdt_mae), ", ",
               R^2 == .(wdt_R2), ")"))
sleg <- bquote(paste("SPAS (", N == .(spas_n), ", ",
               Bias == .(spas_mbias),
               ", ", MAE == .(spas_mae),
               ", ", R^2 == .(spas_R2), ")"))

plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)

legend("topleft", legend = as.expression(c(sleg, wleg)),
col=c("red1","green4"), pch=c(1,3),
                  cex=0.85)

Dennis
On Feb 7, 2014, at 7:54 AM, Douglas M. Hultstrand wrote:

Hello,

I am trying to generate a plot legend that contains calculated summary
statistics, one statistic is R^2.  I have tried several variations using
the commands "expression" and "bqoute" as stated on the R help pages.  I
have not been able to get the R^2 super script correct along with the
calculated statistics.

I provided an example below, what I want is the legend (wdt_leg and
spas_leg) as below but with the R^2 as superscript.

# Example Data
x=c(1,2,3,4);  y=c(1,2,3,4); z=c(1.25,1.5,2.5,3.5)

# first stats based on data, used to populate legend
wdt_n = 50;  wdt_mbias = 0.58
wdt_mae = 2.1;  wdt_R2 = 0.85
# second stats based on data, used to populate legend
spas_n = 50; spas_mbias = 0.58
spas_mae = 2.1; spas_R2 = 0.85

# create legend
wdt_leg <- paste("WDT (N = ", wdt_n,", Bias = ",wdt_mbias,", MAE =
",wdt_mae, ", R2 = ", wdt_R2, ")", sep="")
spas_leg <- paste("SPAS (N = ", spas_n,", Bias = ",spas_mbias,", MAE =
",spas_mae, ", R2 = ", spas_R2, ")", sep="")

# create plot
plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)
leg.txt <- c(spas_leg, wdt_leg)
legend("topleft", legend = leg.txt, col=c("red1","green4"), pch=c(1,3),
cex=0.85)
sublist <-
structure(list(wdt_n = 50, wdt_mbias = 0.58, wdt_mae = 2.1, wdt_R2 = 0.85,
    spas_n = 50, spas_mbias = 0.58, spas_mae = 2.1, spas_R2 = 0.85), .Names = c("wdt_n",
"wdt_mbias", "wdt_mae", "wdt_R2", "spas_n", "spas_mbias", "spas_mae",
"spas_R2"))

legends <-c(
  substitute(
    atop(WDT * group("(", list(N == wdt_n, Bias == wdt_mbias, MAE == wdt_mae ), ")" ),
      R^2 == wdt_R2 ) ,  env=sublist),
  substitute(
    atop(SPAS * group("(", list(N == spas_n, Bias == spas_mbias, MAE == spas_mae ), ")"),
      R^2 == spas_R2 ), env=sublist)  )

# I tried with: as.expression( lapply( exprlist, function(e) bquote(e) ) ) but failed repeatedly.
# In order to get `substitute` to cook the bacon, you need to use real expressions, not text.

plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)
legend("topleft",
   legend = as.expression(legends),
   col=c("red1","green4"), pch=c(1,3),
   cex=0.85)

--
David Winsemius
Alameda, CA, USA

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Thanks everyone for the help.  Dennis, the bquote version work great.
Thanks,
Doug
Here's a bquote version:

x=c(1,2,3,4);  y=c(1,2,3,4); z=c(1.25,1.5,2.5,3.5)

# first stats based on data, used to populate legend
wdt_n = 50;  wdt_mbias = 0.58
wdt_mae = 2.1;  wdt_R2 = 0.85
# second stats based on data, used to populate legend
spas_n = 50; spas_mbias = 0.58
spas_mae = 2.1; spas_R2 = 0.85

wleg <- bquote(paste("WDT (", N == .(wdt_n), ", ",
                Bias == .(wdt_mbias), ", ",
                MAE == .(wdt_mae), ", ",
                R^2 == .(wdt_R2), ")"))
sleg <- bquote(paste("SPAS (", N == .(spas_n), ", ",
                Bias == .(spas_mbias),
                ", ", MAE == .(spas_mae),
                ", ", R^2 == .(spas_R2), ")"))

plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)

legend("topleft", legend = as.expression(c(sleg, wleg)),
col=c("red1","green4"), pch=c(1,3),
                   cex=0.85)

Dennis

On Fri, Feb 7, 2014 at 4:58 PM, David Winsemius <dwinsemius at comcast.net> wrote:
On Feb 7, 2014, at 7:54 AM, Douglas M. Hultstrand wrote:

Hello,

I am trying to generate a plot legend that contains calculated summary
statistics, one statistic is R^2.  I have tried several variations using
the commands "expression" and "bqoute" as stated on the R help pages.  I
have not been able to get the R^2 super script correct along with the
calculated statistics.

I provided an example below, what I want is the legend (wdt_leg and
spas_leg) as below but with the R^2 as superscript.

# Example Data
x=c(1,2,3,4);  y=c(1,2,3,4); z=c(1.25,1.5,2.5,3.5)

# first stats based on data, used to populate legend
wdt_n = 50;  wdt_mbias = 0.58
wdt_mae = 2.1;  wdt_R2 = 0.85
# second stats based on data, used to populate legend
spas_n = 50; spas_mbias = 0.58
spas_mae = 2.1; spas_R2 = 0.85

# create legend
wdt_leg <- paste("WDT (N = ", wdt_n,", Bias = ",wdt_mbias,", MAE =
",wdt_mae, ", R2 = ", wdt_R2, ")", sep="")
spas_leg <- paste("SPAS (N = ", spas_n,", Bias = ",spas_mbias,", MAE =
",spas_mae, ", R2 = ", spas_R2, ")", sep="")

# create plot
plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)
leg.txt <- c(spas_leg, wdt_leg)
legend("topleft", legend = leg.txt, col=c("red1","green4"), pch=c(1,3),
cex=0.85)
sublist <-
structure(list(wdt_n = 50, wdt_mbias = 0.58, wdt_mae = 2.1, wdt_R2 = 0.85,
     spas_n = 50, spas_mbias = 0.58, spas_mae = 2.1, spas_R2 = 0.85), .Names = c("wdt_n",
"wdt_mbias", "wdt_mae", "wdt_R2", "spas_n", "spas_mbias", "spas_mae",
"spas_R2"))

legends <-c(
   substitute(
     atop(WDT * group("(", list(N == wdt_n, Bias == wdt_mbias, MAE == wdt_mae ), ")" ),
       R^2 == wdt_R2 ) ,  env=sublist),
   substitute(
     atop(SPAS * group("(", list(N == spas_n, Bias == spas_mbias, MAE == spas_mae ), ")"),
       R^2 == spas_R2 ), env=sublist)  )

# I tried with: as.expression( lapply( exprlist, function(e) bquote(e) ) ) but failed repeatedly.
# In order to get `substitute` to cook the bacon, you need to use real expressions, not text.

plot(x,y, col="red1", pch=1); lines(x,z, type="p", col="green4",pch=3)
legend("topleft",
    legend = as.expression(legends),
    col=c("red1","green4"), pch=c(1,3),
    cex=0.85)

--
David Winsemius
Alameda, CA, USA

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

---------------------------------
Douglas M. Hultstrand, MS
Senior Hydrometeorologist
Metstat, Inc. Windsor, Colorado
voice: 720.771.5840
email: dmhultst at metstat.com
web: http://www.metstat.com