Hi,
For some reason I have been unable to use the predict function when I
desire the standard error to be calculated too. For example, when I try
the following:
l<- loess(d~x+y, span=span, se=TRUE)
p<- predict(l, se=TRUE)
I get the following error message:
Error in vector("double", length) : vector size cannot be NA
In addition: Warning message:
In N * M1 : NAs produced by integer overflow
But when I try the following:
l<- loess(d~x+y, span=span, se=TRUE)
p<- predict(l, se=FALSE)
I have no problem, and p$fit gives me the desired fitted values. Note
that the only difference in this piece of code is se=FALSE.
My data d is a vector, and x and y are vectors too of the same length.
Any help will be greatly appreciated.
Thanks,
Saurav
cannot calculate standard estimate with predict on loess
4 messages · David Winsemius, Saurav Pathak
On May 3, 2012, at 7:10 PM, Saurav Pathak wrote:
Hi, For some reason I have been unable to use the predict function when I desire the standard error to be calculated too. For example, when I try the following: l<- loess(d~x+y, span=span, se=TRUE) p<- predict(l, se=TRUE)
I don't know what effect the se=TRUE will have in the first call. As far as I can tell there is no such argument to loess(). Could it be that the extranous argument is have an adverse effect on the effort to later use predict (which does have such an argument.)?
I get the following error message:
Error in vector("double", length) : vector size cannot be NA
In addition: Warning message:
In N * M1 : NAs produced by integer overflow
But when I try the following:
l<- loess(d~x+y, span=span, se=TRUE)
p<- predict(l, se=FALSE)
I have no problem, and p$fit gives me the desired fitted values.
Note that the only difference in this piece of code is se=FALSE.
My data d is a vector, and x and y are vectors too of the same length.
Any help will be greatly appreciated.
Thanks,
Saurav
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD Heritage Laboratories West Hartford, CT
On 05/04/2012 10:39 AM, David Winsemius wrote:
On May 3, 2012, at 7:10 PM, Saurav Pathak wrote:
Hi, For some reason I have been unable to use the predict function when I desire the standard error to be calculated too. For example, when I try the following: l<- loess(d~x+y, span=span, se=TRUE) p<- predict(l, se=TRUE)
I don't know what effect the se=TRUE will have in the first call. As far as I can tell there is no such argument to loess(). Could it be that the extranous argument is have an adverse effect on the effort to later use predict (which does have such an argument.)?
Thanks for your reply. I tried the following with the same error message:
l <- loess(d~x+y, span=span)
p <- predict(l, se=TRUE)
Saurav
I get the following error message:
Error in vector("double", length) : vector size cannot be NA
In addition: Warning message:
In N * M1 : NAs produced by integer overflow
But when I try the following:
l<- loess(d~x+y, span=span, se=TRUE)
p<- predict(l, se=FALSE)
I have no problem, and p$fit gives me the desired fitted values.
Note that the only difference in this piece of code is se=FALSE.
My data d is a vector, and x and y are vectors too of the same length.
Any help will be greatly appreciated.
Thanks,
Saurav
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD Heritage Laboratories West Hartford, CT
On May 4, 2012, at 10:52 AM, Saurav Pathak wrote:
On 05/04/2012 10:39 AM, David Winsemius wrote:
On May 3, 2012, at 7:10 PM, Saurav Pathak wrote:
Hi, For some reason I have been unable to use the predict function when I desire the standard error to be calculated too. For example, when I try the following: l<- loess(d~x+y, span=span, se=TRUE) p<- predict(l, se=TRUE)
I don't know what effect the se=TRUE will have in the first call. As far as I can tell there is no such argument to loess(). Could it be that the extranous argument is have an adverse effect on the effort to later use predict (which does have such an argument.)?
Thanks for your reply. I tried the following with the same error message: l <- loess(d~x+y, span=span) p <- predict(l, se=TRUE)
Time for data.
David.
>>>
>>> I get the following error message:
>>>
>>> Error in vector("double", length) : vector size cannot be NA
>>> In addition: Warning message:
>>> In N * M1 : NAs produced by integer overflow
>>>
>>>
>>> But when I try the following:
>>>
>>> l<- loess(d~x+y, span=span, se=TRUE)
>>> p<- predict(l, se=FALSE)
>>>
>>>
>>> I have no problem, and p$fit gives me the desired fitted values.
>>> Note that the only difference in this piece of code is se=FALSE.
>>>
>>> My data d is a vector, and x and y are vectors too of the same
>>> length.
>>>
>>> Any help will be greatly appreciated.
>>>
>>> Thanks,
>>> Saura