a remove question

Dear R People:

I have the following:
ls(pattern="NY*")
[1] "CRAN_df"      "CRAN_df0"     "CRAN_df1"     "CRAN_mat"     "CRAN_sp"
 [6] "CRAN_spdf1"   "CRAN_spdf2"   "CRAN_spdf4"   "delauney_NY"  "dist2_NY"
[11] "dist3_NY"     "Gabriel_NY"   "NY8a_nb"      "rel_neigh_NY" "scot_BNG"
[16] "SOI_NY"
rm(pattern="NY*")
Warning message:
In rm(pattern = "NY*") : object 'NY*' not found

How do I remove all of NY* items, please?  I suspect it might be an sapply issue
thanks,
Erin
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodgess at gmail.com

Dear R People:

I have the following:

ls(pattern="NY*")
[1] "CRAN_df"      "CRAN_df0"     "CRAN_df1"     "CRAN_mat"      
"CRAN_sp"
[6] "CRAN_spdf1"   "CRAN_spdf2"   "CRAN_spdf4"   "delauney_NY"   
"dist2_NY"
[11] "dist3_NY"     "Gabriel_NY"   "NY8a_nb"      "rel_neigh_NY"  
"scot_BNG"
[16] "SOI_NY"
rm(pattern="NY*")
Warning message:
In rm(pattern = "NY*") : object 'NY*' not found

How do I remove all of NY* items, please?  I suspect it might be an  
sapply issue
thanks,
Perhaps:

rm(list= ls()[grep("NY", ls()] )

If there is a pattern argument to rm (I haven't looked)  then it's  
possible that it would have succeeded with pattern="NY",  assuming you  
want any object name with "NY" someplace in it. The "*" looks wrong  
for grepping. ".+" would have looked more greppish, but its not really  
needed.
Erin

-- 
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodgess at gmail.com

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT

On Jan 16, 2011, at 4:08 PM, Erin Hodgess wrote:

Dear R People:

I have the following:

ls(pattern="NY*")
[1] "CRAN_df"      "CRAN_df0"     "CRAN_df1"     "CRAN_mat"      
"CRAN_sp"
[6] "CRAN_spdf1"   "CRAN_spdf2"   "CRAN_spdf4"   "delauney_NY"   
"dist2_NY"
[11] "dist3_NY"     "Gabriel_NY"   "NY8a_nb"      "rel_neigh_NY"  
"scot_BNG"
[16] "SOI_NY"
rm(pattern="NY*")
Warning message:
In rm(pattern = "NY*") : object 'NY*' not found

How do I remove all of NY* items, please?  I suspect it might be an  
sapply issue
thanks,
Perhaps:

OOPs, missing paren:

  rm(list= ls()[grep("NY", ls() )] )

If there is a pattern argument to rm (I haven't looked)  then it's  
possible that it would have succeeded with pattern="NY",  assuming  
you want any object name with "NY" someplace in it. The "*" looks  
wrong for grepping. ".+" would have looked more greppish, but its  
not really needed.

Erin

-- 
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodgess at gmail.com

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
Dear R People:

I have the following:

ls(pattern="NY*")
?[1] "CRAN_df" ? ? ?"CRAN_df0" ? ? "CRAN_df1" ? ? "CRAN_mat" ? ? "CRAN_sp"
?[6] "CRAN_spdf1" ? "CRAN_spdf2" ? "CRAN_spdf4" ? "delauney_NY" ?"dist2_NY"
[11] "dist3_NY" ? ? "Gabriel_NY" ? "NY8a_nb" ? ? ?"rel_neigh_NY" "scot_BNG"
[16] "SOI_NY"
rm(pattern="NY*")
there is no "pattern" argument in rm(), the only reason trying to use
it did not fail is that it has the ... argument to allow many objects
to be passed that you would like removed.
Warning message:
In rm(pattern = "NY*") : object 'NY*' not found
I do not believe  '*' works in regular expressions as I suspect you
are trying to use it.  See ?regexp for details.

How do I remove all of NY* items, please? ?I suspect it might be an sapply issue
There is a list argument to rm() that you can use in conjunction with ls():

rm(list = ls(pattern = "NY"))

Cheers,

Josh
thanks,
Erin

--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodgess at gmail.com

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Joshua Wiley
Ph.D. Student, Health Psychology
University of California, Los Angeles
http://www.joshuawiley.com/
How about

   ls(pattern="NY")
   #rm(list=ls(pattern="NY"))
Dear R People:

I have the following:

ls(pattern="NY*")
 [1] "CRAN_df"      "CRAN_df0"     "CRAN_df1"     "CRAN_mat"     "CRAN_sp"
 [6] "CRAN_spdf1"   "CRAN_spdf2"   "CRAN_spdf4"   "delauney_NY"  "dist2_NY"
[11] "dist3_NY"     "Gabriel_NY"   "NY8a_nb"      "rel_neigh_NY" "scot_BNG"
[16] "SOI_NY"
rm(pattern="NY*")
Warning message:
In rm(pattern = "NY*") : object 'NY*' not found

How do I remove all of NY* items, please?  I suspect it might be an sapply issue
thanks,
Erin

or ....

rm(list=ls(pattern="^NY")) if you only want those objects that begin with
"NY" ...

HTH 

Pete
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