Hi, I want to do the follow thing Input : a <- c(1,3,6,9) b<-c(10,7,20,2) Expected outcome : d<-list(1:10,3:7,6:20,2:9) Thanks !! Tanvir Ahamed G?teborg, Sweden | mashranga at yahoo.com
Generate list if sequence form two vector element
8 messages · Mohammad Tanvir Ahamed, Jim Lemon, Rolf Turner +3 more
Hi Tanvir, Not at all elegant, but: make.seq<-function(x) return(seq(x[1],x[2])) apply(matrix(c(a,b),ncol=2),1,make.seq) Jim On Wed, Jun 22, 2016 at 5:32 PM, Mohammad Tanvir Ahamed via R-help
<r-help at r-project.org> wrote:
Hi, I want to do the follow thing Input : a <- c(1,3,6,9) b<-c(10,7,20,2) Expected outcome : d<-list(1:10,3:7,6:20,2:9) Thanks !! Tanvir Ahamed G?teborg, Sweden | mashranga at yahoo.com
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
On 22/06/16 20:00, Jim Lemon wrote:
Hi Tanvir, Not at all elegant, but: make.seq<-function(x) return(seq(x[1],x[2])) apply(matrix(c(a,b),ncol=2),1,make.seq)
Not sure that this is more "elegant" but it's a one-liner:
lapply(1:length(a),function(i,a,b){a[i]:b[i]},a=a,b=b)
cheers,
Rolf
On Wed, Jun 22, 2016 at 5:32 PM, Mohammad Tanvir Ahamed via R-help <r-help at r-project.org> wrote:
Hi, I want to do the follow thing Input : a <- c(1,3,6,9) b<-c(10,7,20,2) Expected outcome : d<-list(1:10,3:7,6:20,2:9)
Now why didn't I think of that? apply(matrix(c(a,b),ncol=2),1,function(x)x[1]:x[2]) Jim
On Wed, Jun 22, 2016 at 6:14 PM, Rolf Turner <r.turner at auckland.ac.nz> wrote:
On 22/06/16 20:00, Jim Lemon wrote:
Hi Tanvir, Not at all elegant, but: make.seq<-function(x) return(seq(x[1],x[2])) apply(matrix(c(a,b),ncol=2),1,make.seq)
Not sure that this is more "elegant" but it's a one-liner:
lapply(1:length(a),function(i,a,b){a[i]:b[i]},a=a,b=b)
cheers,
Rolf
On Wed, Jun 22, 2016 at 5:32 PM, Mohammad Tanvir Ahamed via R-help <r-help at r-project.org> wrote:
Hi, I want to do the follow thing Input : a <- c(1,3,6,9) b<-c(10,7,20,2) Expected outcome : d<-list(1:10,3:7,6:20,2:9)
There's also mapply(a, b, FUN=seq, SIMPLIFY=FALSE) (turn off simplication so that you don't unexpectedly get a matrix whenever all elements of results have same length. This also affects apply()-based solutions.) ...except that according to original spec, one should ensure a < b. So myseq <- function(a,b) if(a<b) a:b else b:a mapply(a, b, FUN=myseq, SIMPLIFY=FALSE) -pd
On 22 Jun 2016, at 10:42 , Jim Lemon <drjimlemon at gmail.com> wrote: Now why didn't I think of that? apply(matrix(c(a,b),ncol=2),1,function(x)x[1]:x[2]) Jim On Wed, Jun 22, 2016 at 6:14 PM, Rolf Turner <r.turner at auckland.ac.nz> wrote:
On 22/06/16 20:00, Jim Lemon wrote:
Hi Tanvir, Not at all elegant, but: make.seq<-function(x) return(seq(x[1],x[2])) apply(matrix(c(a,b),ncol=2),1,make.seq)
Not sure that this is more "elegant" but it's a one-liner:
lapply(1:length(a),function(i,a,b){a[i]:b[i]},a=a,b=b)
cheers,
Rolf
On Wed, Jun 22, 2016 at 5:32 PM, Mohammad Tanvir Ahamed via R-help <r-help at r-project.org> wrote:
Hi, I want to do the follow thing Input : a <- c(1,3,6,9) b<-c(10,7,20,2) Expected outcome : d<-list(1:10,3:7,6:20,2:9)
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Office: A 4.23 Email: pd.mes at cbs.dk Priv: PDalgd at gmail.com
or as a one-liner mapply(pmin(a, b), pmax(a,b), FUN=seq, SIMPLIFY=FALSE)
On 22/06/2016 10:23, peter dalgaard wrote:
There's also mapply(a, b, FUN=seq, SIMPLIFY=FALSE) (turn off simplication so that you don't unexpectedly get a matrix whenever all elements of results have same length. This also affects apply()-based solutions.) ...except that according to original spec, one should ensure a < b. So myseq <- function(a,b) if(a<b) a:b else b:a mapply(a, b, FUN=myseq, SIMPLIFY=FALSE) -pd
On 22 Jun 2016, at 10:42 , Jim Lemon <drjimlemon at gmail.com> wrote: Now why didn't I think of that? apply(matrix(c(a,b),ncol=2),1,function(x)x[1]:x[2]) Jim On Wed, Jun 22, 2016 at 6:14 PM, Rolf Turner <r.turner at auckland.ac.nz> wrote:
On 22/06/16 20:00, Jim Lemon wrote:
Hi Tanvir, Not at all elegant, but: make.seq<-function(x) return(seq(x[1],x[2])) apply(matrix(c(a,b),ncol=2),1,make.seq)
Not sure that this is more "elegant" but it's a one-liner:
lapply(1:length(a),function(i,a,b){a[i]:b[i]},a=a,b=b)
cheers,
Rolf
On Wed, Jun 22, 2016 at 5:32 PM, Mohammad Tanvir Ahamed via R-help <r-help at r-project.org> wrote:
Hi, I want to do the follow thing Input : a <- c(1,3,6,9) b<-c(10,7,20,2) Expected outcome : d<-list(1:10,3:7,6:20,2:9)
Thanks everyone for the solutions !! Tanvir Ahamed G?teborg, Sweden | mashranga at yahoo.com ----- Original Message ----- From: Keith Jewell <Keith.Jewell at campdenbri.co.uk> To: r-help at stat.math.ethz.ch Sent: Wednesday, 22 June 2016, 11:54 Subject: Re: [R] [FORGED] Re: Generate list if sequence form two vector element or as a one-liner mapply(pmin(a, b), pmax(a,b), FUN=seq, SIMPLIFY=FALSE)
On 22/06/2016 10:23, peter dalgaard wrote:
There's also mapply(a, b, FUN=seq, SIMPLIFY=FALSE) (turn off simplication so that you don't unexpectedly get a matrix whenever all elements of results have same length. This also affects apply()-based solutions.) ...except that according to original spec, one should ensure a < b. So myseq <- function(a,b) if(a<b) a:b else b:a mapply(a, b, FUN=myseq, SIMPLIFY=FALSE) -pd
On 22 Jun 2016, at 10:42 , Jim Lemon <drjimlemon at gmail.com> wrote: Now why didn't I think of that? apply(matrix(c(a,b),ncol=2),1,function(x)x[1]:x[2]) Jim On Wed, Jun 22, 2016 at 6:14 PM, Rolf Turner <r.turner at auckland.ac.nz> wrote:
On 22/06/16 20:00, Jim Lemon wrote:
Hi Tanvir, Not at all elegant, but: make.seq<-function(x) return(seq(x[1],x[2])) apply(matrix(c(a,b),ncol=2),1,make.seq)
Not sure that this is more "elegant" but it's a one-liner:
lapply(1:length(a),function(i,a,b){a[i]:b[i]},a=a,b=b)
cheers,
Rolf
On Wed, Jun 22, 2016 at 5:32 PM, Mohammad Tanvir Ahamed via R-help <r-help at r-project.org> wrote:
Hi, I want to do the follow thing Input : a <- c(1,3,6,9) b<-c(10,7,20,2) Expected outcome : d<-list(1:10,3:7,6:20,2:9)
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Hi
what about
mapply(":", a, b)
Sometimes R can behave like a magic.
Cheers
Petr
-----Original Message----- From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Jim Lemon Sent: Wednesday, June 22, 2016 10:01 AM To: Mohammad Tanvir Ahamed <mashranga at yahoo.com> Cc: R-help Mailing List <r-help at r-project.org> Subject: Re: [R] Generate list if sequence form two vector element Hi Tanvir, Not at all elegant, but: make.seq<-function(x) return(seq(x[1],x[2])) apply(matrix(c(a,b),ncol=2),1,make.seq) Jim On Wed, Jun 22, 2016 at 5:32 PM, Mohammad Tanvir Ahamed via R-help <r- help at r-project.org> wrote:
Hi, I want to do the follow thing Input : a <- c(1,3,6,9) b<-c(10,7,20,2) Expected outcome : d<-list(1:10,3:7,6:20,2:9) Thanks !! Tanvir Ahamed G?teborg, Sweden | mashranga at yahoo.com
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting- guide.html and provide commented, minimal, self-contained, reproducible code.
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