dimnames in an array(I'll be grateful if this message will be passed to all list users)

Hi Michael,
Thanks for help on double brackets: I wasn't aware of this use of them.

I went back to readjust my array so the dimnames(data11a)[[2]] would have
two elements, and remade the array to include the new dimnames:

dimnames(data11a)[[2]]=c("V","R")

so that inside the second car of the train would
be two items?

There seems to be no way to define dimnames(data11a)[2] to be two elements
rather than one[as you say we have no way to combine the elements of the
train except using the train].

So having tried to do what I can to make the
middle element of the list to two rather than one, I rerun the analysis with
the same result.

if I read the thing right, regardless of how I define the "inside" of the
boxcar, the analysis that I referred to

                 res11a = inneropt(coefs, times=times, data=data11a,
lik=lik,
                 proc=proc, pars=spars, in.meth='nlminb',
control.in=control.out)

still won't look at the 'contents' of the car, but gives the same message:

                  Error in `colnames<-`(`*tmp*`, value = c("V", "R")) :
                  length of 'dimnames' [2] not equal to array extent


I've tried a couple of other things like, after defining the second boxcar
as:

                  dimnames(data11a)[[2]]=c("V","R")


then


                   dimnames(data11a)[2]=list(dimnames(data11a)[[2]])


but this last generates an error.

Somehow I think that that the clue to the thing is in the error message:
what I see[ with my untrained eye] is that there should be some way to
reconcile the three-- colnames, dimnames and the array- to a greater degree
than their present agreement.
Am I right?
regards,
Russell

Tue, 14 Aug 2012 01:27:50 -0400 ?? "R. Michael Weylandt"
<michael.weylandt at gmail.com>:

On Mon, Aug 13, 2012 at 5:10 AM, aleksandr russell <sss736 at gmail.com> wrote:

Hello,

I'm hoping someone with a wide experience with R may be able to see
what the program is trying to tell me.

I've got an array:

y1=rnorm(41,0.2)
y2=rnorm(41,0.2)
y3=rbind(y1,y2)



data11<-array(0,c(41,2,2))
data11[,1,]=y3
data11[,2,]=y3
rownames(data11)<-rownames(data11, do.NULL = FALSE, prefix = "Obs.")
colnames=c("V","R")
varnames=c("one","two")
dimnames(data11)<-list(rownames(data11), varnames, colnames)



data11a<-as.array(data11, dimnames=dimnames(data11))

# No effect here
 identical(data11, data11a) # TRUE

The analysis that I would like to do with R(CollocInfer) runs as
follows(I print for the sake of introduction here though to run this
line of code requires extensive setup)

res11a = inneropt(coefs, times=times, data=data11a, lik=lik,
proc=proc, pars=spars, in.meth='nlminb', control.in=control.out)



The response I get is

Error in 'colnames<-'('*tmp*', value = c("V","R")) :
length of 'dimnames' [2] not equal to array extent



It seems to me that there is a fundamental match of 'dimnames' with
the array that is being referred to.

I have learned that the normal length of dimnames for an array is one
for each element in the list: thus as I've set up the array, the
length(dimnames(data11a)[2]) gives me

[1]

I believe you are looking for

length(dimnames(data11a)[[2]]) # 2

Look into the difference between `[` and `[[` for subsetting a list.
See ?Extract for the gorey details, but I like my little train
metaphor:

If the list "x", is a train: x[2] is the "sub-train" consisting only
of the second car, while x[[2]] is the contents of that second car.
Hence we can do x[1:3] to give a well defined train, but not x[[1:3]]
because we have no way to combine the elements of the first three cars
other than using a train.

Cheers,
Michael

I would like to ask :Is it not evident from R's response that there is
some other possibility for the dimnames[2] of the array?

If so, what is it?

regards,
A