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replacing with NA

3 messages · Mintewab Bezabih, R. Michael Weylandt, PIKAL Petr

#
Dear R users, 

I was wondering  how I can replace the values of a vector with the values from in another vector in the same row

For example, how can I replace the value of x below with NA when the value of Z in the same row is NA?
x <-1:20
z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,17, NA, 12, 10)


Many thanks
Mintewab

________________________________________
Fr?n: Mintewab Bezabih
Skickat: den 15 maj 2012 15:53
Till: r-help at r-project.org
Kopia: r-help at r-project.org
?mne: missing observations

Dear R users,

I have missing observations in my data that I remove in my analysis. I am able to run my codes alright but I want the non missing values to be correctly identified and therefore want to tag my id vector along in my results. Since the vector of ids has no role in the analysis, I dont know how to include it.



Here is my reprducable example:and my id is the vector I want to add to the analysis somehow so that my missing values are identified. I cannot use  na.action function and that is why I have to drop my missing obesevations beforehand.


library(fields)
x <-1:20
y<- runif(20)
z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,
17, NA, 12, 10)
id <-1:20

mydataset<-data.frame(x, y, z)
temperature[complete.cases(mydataset),]

 x<- temperature[, c(1)]
y<- temperature[, c(2)]
z<- temperature[, c(3)]

tpsfit <- Tps(cbind(x, y), z, scale.type="unscaled")




Many thanks as always.
Regards,
Mintewab
#
x[is.na(z)] <- NA

This might send you a nasty bug if x and z are different lengths
though -- just a head's up.

Michael

On Wed, May 16, 2012 at 12:55 PM, Mintewab Bezabih
<Mintewab.Bezabih at economics.gu.se> wrote:
#
Another option
x*!is.na(z)*z

Regards
Petr
NA, 12, 10)

            
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