Quick question!

Thanks very much to all who answered my question
yesterday on loops.

Just a further quick question:

If I have this:

for(i in 1:n) {
  subset <- data[which(data$id==i),]

which returns the rows where I have the variable ID=1,
how can I tell the same statement to return just
column Y where ID=i?

I have tried this

for(i in 1:n) {
  subset <- data[which(data$id==i),data$Y]

for(i in 1:n) {
   subset <- data[which(data$id==i),"Y"]

maybe?

but it doesn't work

Thanks again
Isabel

***********************************************************************
Jens Nieschulze


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If I have this:

for(i in 1:n) {
  subset <- data[which(data$id==i),]

which returns the rows where I have the variable ID=1,
how can I tell the same statement to return just
column Y where ID=i?

Try

subset <- data$Y[data$id==i]

Cheers,

Winfried
----------------------------------
E-Mail: Winfried Theis <theis at statistik.uni-dortmund.de>
Date: 31-Oct-01
Time: 13:06:37
Dipl.-Math. Winfried Theis, Fachbereich Statistik, Graduiertenkolleg
"Angewandte Statistik"
Universität Dortmund, 44221 Dortmund
Tel.: +49-231-755-5903  FAX: +49-231-755-4387
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Isabel Jones <statsonthebrain at yahoo.com> writes:

Just a further quick question:

If I have this:

for(i in 1:n) {
 subset <- data[which(data$id==i),]

which returns the rows where I have the variable ID=1,
how can I tell the same statement to return just
column Y where ID=i?

The subset() function does this:

        For(i in 1:n) {
                ss <- subset(data, id == i, Y)
                }

Mark


--
Mark Myatt


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