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histogram

6 messages · Francis Keyes, David Winsemius

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On Feb 5, 2012, at 8:31 PM, Francis Keyes wrote:

            
hist() returns an object with both "counts" and "density". If you had  
a reference population it should be a fairly simple matter to use one  
or the other of those.
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On Feb 6, 2012, at 12:23 PM, Francis Keyes wrote:

            
It is difficult to specify "how" when we have no "what". The "what" is  
your responsibility, not ours. My thought was to use the ratio of the  
results of hist() on the two populations  which would then be offered  
back to hist or barplot. ....which (of course) requires that the  
'breaks'  be the same. Provide an example of your R representations of  
the reference population and tested population and all will become  
clear.

(And learn to post in plain text, please.)
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Hi David,

I have 2 tables, each with several columns and rows of data.  I am
only interested in the data from column 6, which contains values in
the range -PI to PI.  I want to plot the data from tableD with the y
axis denoting percentage with respect to tableR.  So if data points in
the break 2 - 3 appear half as often in tableD as in tableR, the y
axis should show 50 percent.  Does that make sense?
I've been plotting the data like this to date:

hist(tableD[,6],ylab="frequency", xlab="angle")

Thanks a lot for your help
On Mon, Feb 6, 2012 at 1:31 PM, David Winsemius <dwinsemius at comcast.net> wrote:
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On Feb 6, 2012, at 5:26 PM, Francis Keyes wrote:

            
It all makes sense, (and it made sense before) , but your  
responsibility is to provide data.

(Contrats on plain text lesson successfully met.)
David Winsemius, MD
West Hartford, CT