3 messages · mstepano, David Winsemius
Hi all, I have a list ov vectors of enequal lenght and need to check is the given vector in list.
v1<-c(1,2) v2<-c(1,2,3) v3<-c(1,3) allv<-list(v1,v2,v3) somev<-c(1,2) somev%in%allv
[1] FALSE FALSE Hence, %in% checks that elements of vector somev are in list. How it is possible to check that somev is element of list? -- View this message in context: http://r.789695.n4.nabble.com/Searching-elements-in-list-tp3987066p3987066.html Sent from the R help mailing list archive at Nabble.com.
I forget to mention that the vectors are ordered. I think that one of the possible solutions is to use lapply, i.e., < T %in% lapply(allv, function(x,y) all.equal(x,y),y=somev) [1] TRUE -- View this message in context: http://r.789695.n4.nabble.com/Searching-elements-in-list-tp3987066p3987487.html Sent from the R help mailing list archive at Nabble.com.
I forget to mention that the vectors are ordered. I think that one of the possible solutions is to use lapply, i.e., < T %in% lapply(allv, function(x,y) all.equal(x,y),y=somev) [1] TRUE
all.equal worked fine when the answer was 'true' but not so well in my hands when it was 'false'. Also not a good idea to replace the base definition of %in%. > any( sapply( allv, identical, v1) ) [1] TRUE > any( sapply( allv, identical, c(3,3,4)) ) [1] FALSE `%l.in%` <- function(vec,lis) any( sapply( lis, identical, vec) ) Use: > v1 %l.in% allv [1] TRUE -- David Winsemius, MD Heritage Laboratories West Hartford, CT