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how to simulate a time series

2 messages · bogdan romocea, Brian Ripley

#
Dear useRs,

I want to simulate a time series (stationary; the distribution of
values is skewed to the right; quite a few ARMA absolute standardized
residuals above 2 - about 8% of them). Is this the right way to do it?
#--------------------------------
load("rdtb")	#the time series
Min.  1st Qu.   Median     Mean  3rd Qu.     Max. 
-1.11800 -0.65010 -0.09091  0.30390  1.12500  2.67600 

farma <- arima(rdtb,order=c(1,0,1),include.mean=T)
ar1        ma1  intercept 
0.58091575 0.02313803 0.30417062 

sim <- list(NULL)	#simulated
for (i in 1:5) {
	sim[[i]] <- as.vector(arima.sim(list(ar=c(farma[["coef"]][1]),
		ma=c(farma[["coef"]][2])),n=length(rdtb),innov=rdtb))
	}
allsim <- as.data.frame(sim)
colnames(allsim) <- paste("sim",1:5,sep="")
all <- cbind(rdtb,allsim)
#--------------------------------

I don't understand why the simulation runs generate virtually identical
values:
rdtb     sim1     sim2     sim3     sim4     sim5
100  2.3863636 1.065661 1.065661 1.065661 1.065661 1.065661
101  1.9318182 2.606093 2.606093 2.606093 2.606093 2.606093
102  2.2954545 3.854074 3.854074 3.854074 3.854074 3.854074
103  2.5882353 4.880240 4.880240 4.880240 4.880240 4.880240
104  2.0227273 4.917622 4.917622 4.917622 4.917622 4.917622
105 -0.1521739 2.751352 2.751352 2.751352 2.751352 2.751352

It appears I may be missing something (very) basic, but don't know
what.

Thank you,
b.
#
On Thu, 31 Mar 2005, bogdan romocea wrote:

            
The meaning of `innovations'.  The innovations determine the series, so 
you asked for the same series five times.  In the reference, the 
innovations are e[t].