Is there any logical reason why glm prints out the labels of factor levels after variable names when baseline contrasts (contr.treatment) are used but the codes for the levels when mean contrasts (contr.sum) are used? Jim -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
factors in glm
4 messages · Jim Lindsey, Ross Darnell, Peter Dalgaard
Jim Lindsey <jlindsey at alpha.luc.ac.be> writes:
Is there any logical reason why glm prints out the labels of factor levels after variable names when baseline contrasts (contr.treatment) are used but the codes for the levels when mean contrasts (contr.sum) are used? Jim
Hmmm. We have in contr.sum
cont <- array(0, c(lenglev, lenglev - 1), list(levels,
NULL))
cont[col(cont) == row(cont)] <- 1
cont[lenglev, ] <- -1
I'd put list(level,levels[-lenglev]) there, but someone seems to have
decided that it wouldn't make sense? (I would also have coded the
value as rbind(diag(lenglev-1),-1), but that's another matter).
In the case of Helmert contrasts, one would by similar logic end up
with the same names as for contr.treatment, which would be confusing
(as if Helmert contrasts weren't confusing enough...!). Of course, you
currently cannot tell the difference between .sum and .helmert - you
only get a signal that something is "unusual".
What I'd really want is a way of labeling the summary() output with
the kind of contrast used. Ideally, in my mind, summary.(g)lm should
produce output like (for an age x sex interaction with age using
contr.sum and sex using contr.treat)
age(S).sex(T)
0-40.M
41-50.M
51-60.M
O__ ---- Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk) FAX: (+45) 35327907 -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._
I understand that there are two ways to define the response for binomial case in R(S). 1) As a vector of p's for which the number of trials is assumed to be 1 2) As a 2 column matrix, the first being the number of sucesses, the second being the number of failures. Before the weighted least squares function is used, the prior weights need to be generated as well as the numer of success converted to a proportion. Two questions I have concern the 2nd case. Does the model.response function convert the number of successes into a propn? I couldn't see that it did. and how is the denominator included as a (prior) weight? I would appreciate any help with these questions. Thanks Ross Darnell
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R.E.Darnell at newcastle.ac.uk (R.E. Darnell) writes:
I understand that there are two ways to define the response for binomial case in R(S). 1) As a vector of p's for which the number of trials is assumed to be 1 2) As a 2 column matrix, the first being the number of sucesses, the second being the number of failures.
3) as a vector of p's, the number of trials given in the weights= argument
Two questions I have concern the 2nd case. Does the model.response function convert the number of successes into a propn? I couldn't see that it did.
Nope. That's not it's job. It just pulls out the relevant bits of the model frame.
and how is the denominator included as a (prior) weight?
Have a look at the initialize expression as defined in binomial().
O__ ---- Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk) FAX: (+45) 35327907 -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._