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5 messages · Helios de Rosario, Florian Weiler, Berend Hasselman +1 more

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Helios de Rosario
# 
-- 
Helios de Rosario Mart?nez
 
 Researcher
escribi?:
mice
the
follows:
must
Hi Florian,

Please give more context. There are various reasons why that could
fail. Is your list "set" defined before starting to assign values?

Try:
set <- vector("list",10)
before the loop.



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Florian Weiler
# 
Thanks for the answer, and sorry if I was not clear.

So I run the data imputation using mice with 10 chains and then I get a
mids-object. From that object I can then extract 10 data sets using the
complete(imp, n) command (with n=c(1:10)).

Now I can type this out 10 times:
set1 <- complete(imp, 1) 
set2 <- complete(imp, 2)
etc.

Each of these set1 to set10 will be a data frame. That all is easy enough,
but I would like to do this in a loop and create the same 10 data sets. 

If I use the command proposed by you, then the loop works but again the 10
data sets are stored in only one single object (a list) when I would like to
create 10 separate data sets. 

Is that enough information?

Thanks again,
Florian

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Berend Hasselman
#
On 22-02-2012, at 14:40, Florian Weiler wrote:

            

      
      
      
    

        
How about this

for( k in 1:10 )  assign(paste("set",k,sep=""), complete(imp,k))


Berend Hasselman

  
  


  


      

    

    

      
      

        


  

        

      Milan Bouchet-Valat
    

    

      
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Le mercredi 22 f?vrier 2012 ? 05:40 -0800, Florian Weiler a ?crit :

            

      
      
      
    

        
With the suggested solution, you get a list of data sets. You can access
each data set separately as if it was a separate object, e.g. using
set[[1]]. It's usually more practical to have all objects in a list,
this allows you to run actions on all of them easily using lapply() and
things like that.

Hope this helps