Dear R-helpers, I am a beginner using R. This is the first question in this list. My question, Is there possible to make combinations with two part column? If I have a number 1,2,3,4,5,6,7,8. I need the result something like below: 1,2,3,4,5 6,7,8 1,2,3,4,7 5,6,8 2,3,4,5,6 1,7,8 1,2,3,6,7 4,5,8 1,2,3,4,8 5,6,7 3,4,6,7,8 1,2,5 .... I would be very happy if anyone could help me. Best regards, Sofyan
Combinations with two part column
5 messages · Sofyan Iyan, Gabor Grothendieck
On 5/17/05, Sofyan Iyan <sofyan.iyan at gmail.com> wrote:
Dear R-helpers, I am a beginner using R. This is the first question in this list. My question, Is there possible to make combinations with two part column? If I have a number 1,2,3,4,5,6,7,8. I need the result something like below: 1,2,3,4,5 6,7,8 1,2,3,4,7 5,6,8 2,3,4,5,6 1,7,8 1,2,3,6,7 4,5,8 1,2,3,4,8 5,6,7 3,4,6,7,8 1,2,5 ....
Try this: library(gtools) t(apply(combinations(8,5), 1, function(x) c(x,setdiff(1:8, x))))
Thanks for you quick answer. Could I extend my question? How to make the result for each rows with comma ",";
library(gtools) comb8.5 <- t(apply(combinations(8,5), 1, function(x) c(x,setdiff(1:8, x)))) comb8.5[,1:5]
[,1] [,2] [,3] [,4] [,5]
[1,] 1 2 3 4 5
[2,] 1 2 3 4 6
[3,] 1 2 3 4 7
[4,] 1 2 3 4 8
[5,] 1 2 3 5 6
[6,] 1 2 3 5 7
...
I mean like:
1, 2, 3, 4, 5
1, 2, 3, 4, 6
1, 2, 3, 4, 7
1, 2, 3, 4, 8
1, 2, 3, 5, 6
1, 2, 3, 5, 7
comb8.5[,6:8]
[,1] [,2] [,3]
[1,] 6 7 8
[2,] 5 7 8
[3,] 5 6 8
[4,] 5 6 7
[5,] 4 7 8
[6,] 4 6 8
...
this below like:
6, 7, 8
5, 7, 8
5, 6, 8
5, 6, 7
4, 7, 8
4, 6, 8
Best,
Sofyan
On 5/17/05, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:
On 5/17/05, Sofyan Iyan <sofyan.iyan at gmail.com> wrote:
Dear R-helpers, I am a beginner using R. This is the first question in this list. My question, Is there possible to make combinations with two part column? If I have a number 1,2,3,4,5,6,7,8. I need the result something like below: 1,2,3,4,5 6,7,8 1,2,3,4,7 5,6,8 2,3,4,5,6 1,7,8 1,2,3,6,7 4,5,8 1,2,3,4,8 5,6,7 3,4,6,7,8 1,2,5 ....
Try this: library(gtools) t(apply(combinations(8,5), 1, function(x) c(x,setdiff(1:8, x))))
Try write.table: write.table(comb8.5[,1:5], sep = ",", row.names = FALSE, col.names = FALSE) write.table(comb8.5[,6:8], sep = ",", row.names = FALSE, col.names = FALSE)
On 5/17/05, Sofyan Iyan <sofyan.iyan at gmail.com> wrote:
Thanks for you quick answer. Could I extend my question? How to make the result for each rows with comma ",";
library(gtools) comb8.5 <- t(apply(combinations(8,5), 1, function(x) c(x,setdiff(1:8, x)))) comb8.5[,1:5]
[,1] [,2] [,3] [,4] [,5] [1,] 1 2 3 4 5 [2,] 1 2 3 4 6 [3,] 1 2 3 4 7 [4,] 1 2 3 4 8 [5,] 1 2 3 5 6 [6,] 1 2 3 5 7 ... I mean like: 1, 2, 3, 4, 5 1, 2, 3, 4, 6 1, 2, 3, 4, 7 1, 2, 3, 4, 8 1, 2, 3, 5, 6 1, 2, 3, 5, 7
comb8.5[,6:8]
[,1] [,2] [,3]
[1,] 6 7 8
[2,] 5 7 8
[3,] 5 6 8
[4,] 5 6 7
[5,] 4 7 8
[6,] 4 6 8
...
this below like:
6, 7, 8
5, 7, 8
5, 6, 8
5, 6, 7
4, 7, 8
4, 6, 8
Best,
Sofyan
On 5/17/05, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:
On 5/17/05, Sofyan Iyan <sofyan.iyan at gmail.com> wrote:
Dear R-helpers, I am a beginner using R. This is the first question in this list. My question, Is there possible to make combinations with two part column? If I have a number 1,2,3,4,5,6,7,8. I need the result something like below: 1,2,3,4,5 6,7,8 1,2,3,4,7 5,6,8 2,3,4,5,6 1,7,8 1,2,3,6,7 4,5,8 1,2,3,4,8 5,6,7 3,4,6,7,8 1,2,5 ....
Try this: library(gtools) t(apply(combinations(8,5), 1, function(x) c(x,setdiff(1:8, x))))
______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Dear to Gabor Grothendieck and James Holtman, Thank you for giving me so much of your time to solve my problem. Many thanks and best regards, Sofyan
On 5/17/05, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:
Try write.table: write.table(comb8.5[,1:5], sep = ",", row.names = FALSE, col.names = FALSE) write.table(comb8.5[,6:8], sep = ",", row.names = FALSE, col.names = FALSE) On 5/17/05, Sofyan Iyan <sofyan.iyan at gmail.com> wrote:
Thanks for you quick answer. Could I extend my question? How to make the result for each rows with comma ",";
library(gtools) comb8.5 <- t(apply(combinations(8,5), 1, function(x) c(x,setdiff(1:8, x)))) comb8.5[,1:5]
[,1] [,2] [,3] [,4] [,5] [1,] 1 2 3 4 5 [2,] 1 2 3 4 6 [3,] 1 2 3 4 7 [4,] 1 2 3 4 8 [5,] 1 2 3 5 6 [6,] 1 2 3 5 7 ... I mean like: 1, 2, 3, 4, 5 1, 2, 3, 4, 6 1, 2, 3, 4, 7 1, 2, 3, 4, 8 1, 2, 3, 5, 6 1, 2, 3, 5, 7
comb8.5[,6:8]
[,1] [,2] [,3]
[1,] 6 7 8
[2,] 5 7 8
[3,] 5 6 8
[4,] 5 6 7
[5,] 4 7 8
[6,] 4 6 8
...
this below like:
6, 7, 8
5, 7, 8
5, 6, 8
5, 6, 7
4, 7, 8
4, 6, 8
Best,
Sofyan
On 5/17/05, Gabor Grothendieck <ggrothendieck at gmail.com> wrote:
On 5/17/05, Sofyan Iyan <sofyan.iyan at gmail.com> wrote:
Dear R-helpers, I am a beginner using R. This is the first question in this list. My question, Is there possible to make combinations with two part column? If I have a number 1,2,3,4,5,6,7,8. I need the result something like below: 1,2,3,4,5 6,7,8 1,2,3,4,7 5,6,8 2,3,4,5,6 1,7,8 1,2,3,6,7 4,5,8 1,2,3,4,8 5,6,7 3,4,6,7,8 1,2,5 ....
Try this: library(gtools) t(apply(combinations(8,5), 1, function(x) c(x,setdiff(1:8, x))))
______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html