If all vectors in the list have the same length, why not use a matrix? Then you'd just transpose the matrix if you need to. If you really have to have it as a list, here's one possibility:
x <- list("1"=c(a=1, b=2, c=3), "2"=c(a=4, b=5, c=6))
x
$"1" a b c 1 2 3 $"2" a b c 4 5 6
as.list(as.data.frame(t(matrix(unlist(x), nrow=3))))
$V1 [1] 1 4 $V2 [1] 2 5 $V3 [1] 3 6 Andy
From: Jan Hummel Hi. Can anyone suggest a simple way to re-sort in R a list of vectors of the following form? input $"1" a b c 1 2 3 $"2" a b c 4 5 6 Output should be something like: "a" "1" 1 "2" 4 "b" "1" 2 "2" 5 "c" "1" 3 "2" 6 I've been futzing with mapply(), outer(), split(), rbind() and so on but haven't found an elegant solution. Thanks, Jan. P.S. E-mailed CCs of posted replies appreciated.
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