Multiple graphs > boxplot

Dear all

I am trying to represent a dependent variable (treatment) against different independent variables (v1, v2, v3....v20). I am using the following command:


However, it provides me only one graph for v1~treatment. For the other comparisons, I have to repeat the same command but changing the parameters. My intentions is to get different plots in just one sheet using only one command. Is it possible to join the same order for all the comparisons in only one command?

Two options:
A)
Melt the dataframe with reshape2::melt
then use boxplot( value ~ interaction(variable,treatment) )

B) 
Melt the dataframe
Use bwplot in lattice with a slightly more full featured formula interface

bwplot(value~cat|variable, data=amelt)

Option B is more beautiful in my opinion.
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David Winsemius, MD
Alameda, CA, USA

Hello,

I've once written a function that does more or less what you want, but 
it has no formula interface.

# Input:
#    x - matrix or data.frame of numeric vectors to graph
#    by - a factor or coercible to factor
multi.boxplot <- function(x, by, col=0, ...){
     x <- as.data.frame(x)
     uniq.by <- unique(by)
     by <- factor(by)
     len <- length(uniq.by) - 1
     n <- ncol(x)
     n1 <- n + 1
     col <- rep(col, n)[seq_len(n)]
     boxplot(x[[ 1 ]] ~ by, at = 0:len*n1 + 1,
         xlim = c(0, (len + 1)*n1), ylim = range(unlist(x)), xaxt = "n", 
col=col[1], ...)
     for(i in seq_len(n)[-1])
         boxplot(x[[i]] ~ by, at = 0:len*n1 + i, xaxt = "n", add = TRUE, 
col=col[i], ...)
     axis(1, at = 0:len*n1 + n1/2, labels = uniq.by, tick = TRUE)
}


a <- matrix(data=runif(300,max=2), nrow=100, ncol=3)
fac <- sample(letters[1:4], 100, TRUE)

multi.boxplot(a, fac)


Hope this helps,

Rui Barradas
Em 05-10-2012 17:01, David Gramaje escreveu:

Dear all

I am trying to represent a dependent variable (treatment) against different independent variables (v1, v2, v3....v20). I am using the following command:

boxplot(v1~treatment,data=y, main="xxxxxx",xlab="xxxxxx", ylab="xxxxxx")

However, it provides me only one graph for v1~treatment. For the other comparisons, I have to repeat the same command but changing the parameters. My intentions is to get different plots in just one sheet using only one command. Is it possible to join the same order for all the comparisons in only one command?

Thanks
David
  		 	   		
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Does something like this make any sense?

library(reshape2)
library(ggplot2)
yy  <-  structure(list(A = c(23, 21, 21, 20, 19, 19), B = c(20, 18, 20, 
19, 20, 18), C = c(15, 15, 15, 12, 13, 13)), .Names = c("A", 
"B", "C"), class = "data.frame", row.names = c(NA, -6L))

y1  <-  melt(yy)  # using reshape2 

ggplot(y1, aes(variable, value))+ geom_boxplot() 

# or

ggplot(y1, aes(variable, value))+ geom_boxplot()  + facet_grid(variable ~ .)




John Kane
Kingston ON Canada

-----Original Message-----
From: dagrape at hotmail.com
Sent: Fri, 5 Oct 2012 18:01:39 +0200
To: r-help at r-project.org
Subject: [R] Multiple graphs > boxplot



Dear all

I am trying to represent a dependent variable (treatment) against
different independent variables (v1, v2, v3....v20). I am using the
following command:

boxplot(v1~treatment,data=y, main="xxxxxx",xlab="xxxxxx", ylab="xxxxxx")

However, it provides me only one graph for v1~treatment. For the other
comparisons, I have to repeat the same command but changing the
parameters. My intentions is to get different plots in just one sheet
using only one command. Is it possible to join the same order for all the
comparisons in only one command?

Thanks
David

	[[alternative HTML version deleted]]

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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