I am trying to drop a column of a data frame. The code below attempts to drop a numeric column (which does not work but gives no error or warning) and a factor column (which does not work but gives an error).
I would appreciate someone telling me why my code does not work, and suggesting code that will work.
Thanks,
John
rm(dfxyz,dfxz,dfxy)
# create the data frame.
dfxyz <- data.frame(x=1:10,y=11:20,z=factor(c(rep(0,5),rep(1,5))))
dfxyz
names(dfxyz)
# try to drop y column
# does not work, does not produce error message
dfxz <- dfxyz[,-(dfxyz$y)]
dfxz
# try to drop z column
# does not work, produces error message:
# In Ops.factor(df$z) : - not meaningful for factors
dfxy <- dfxyz[,-dfxyz$z]
dfxy
John David Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
Baltimore, MD 21201-1524
(Phone) 410-605-7119
(Fax) 410-605-7913 (Please call phone number above prior to faxing)
Confidentiality Statement:
This email message, including any attachments, is for th...{{dropped:6}}
Drop column from a data frame
4 messages · John Sorkin, jim holtman, Phil Spector +1 more
assign NULL to the column:
dfxyz <- data.frame(x=1:10,y=11:20,z=factor(c(rep(0,5),rep(1,5)))) dfxyz
x y z 1 1 11 0 2 2 12 0 3 3 13 0 4 4 14 0 5 5 15 0 6 6 16 1 7 7 17 1 8 8 18 1 9 9 19 1 10 10 20 1
dfxyz$y <- NULL dfxyz
x z 1 1 0 2 2 0 3 3 0 4 4 0 5 5 0 6 6 1 7 7 1 8 8 1 9 9 1 10 10 1
On Sun, Dec 26, 2010 at 8:22 PM, John Sorkin
<jsorkin at grecc.umaryland.edu> wrote:
I am trying to drop a column of a data frame. The code below attempts to drop a numeric column (which does not work but gives no error or warning) and a factor column (which does not work but gives an error).
I would appreciate someone telling me why my code does not work, and suggesting code that will work.
Thanks,
John
rm(dfxyz,dfxz,dfxy)
# create the data frame.
dfxyz <- data.frame(x=1:10,y=11:20,z=factor(c(rep(0,5),rep(1,5))))
dfxyz
names(dfxyz)
# try to drop y column
# does not work, does not produce error message
dfxz <- dfxyz[,-(dfxyz$y)]
dfxz
# try to drop z column
# does not work, produces error message:
# In Ops.factor(df$z) : - not meaningful for factors
dfxy <- dfxyz[,-dfxyz$z]
dfxy
John David Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
Baltimore, MD 21201-1524
(Phone) 410-605-7119
(Fax) 410-605-7913 (Please call phone number above prior to faxing)
Confidentiality Statement:
This email message, including any attachments, is for ...{{dropped:17}}
John -
You can use a syntax similar to what you've tried with
the select= argument of the subset function:
subset(dfxyz,select=-y)
x z 1 1 0 2 2 0 . . .
subset(dfxyz,select=-z)
x y 1 1 11 2 2 12 . . . - Phil Spector Statistical Computing Facility Department of Statistics UC Berkeley spector at stat.berkeley.edu
On Sun, 26 Dec 2010, John Sorkin wrote:
I am trying to drop a column of a data frame. The code below attempts to drop a numeric column (which does not work but gives no error or warning) and a factor column (which does not work but gives an error).
I would appreciate someone telling me why my code does not work, and suggesting code that will work.
Thanks,
John
rm(dfxyz,dfxz,dfxy)
# create the data frame.
dfxyz <- data.frame(x=1:10,y=11:20,z=factor(c(rep(0,5),rep(1,5))))
dfxyz
names(dfxyz)
# try to drop y column
# does not work, does not produce error message
dfxz <- dfxyz[,-(dfxyz$y)]
dfxz
# try to drop z column
# does not work, produces error message:
# In Ops.factor(df$z) : - not meaningful for factors
dfxy <- dfxyz[,-dfxyz$z]
dfxy
John David Sorkin M.D., Ph.D.
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
Baltimore, MD 21201-1524
(Phone) 410-605-7119
(Fax) 410-605-7913 (Please call phone number above prior to faxing)
Confidentiality Statement:
This email message, including any attachments, is for th...{{dropped:6}}
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On Dec 26, 2010, at 8:22 PM, John Sorkin wrote:
I am trying to drop a column of a data frame. The code below attempts to drop a numeric column (which does not work but gives no error or warning) and a factor column (which does not work but gives an error). I would appreciate someone telling me why my code does not work, and suggesting code that will work.
You are misusing the syntax of the "[" operation. When using negative
indices you can only use numeric or logical values :
?"["
Character indices always need to be "positive".
dfxyz[ , -2] # works
dfxyz[ , c(T,F,T)] # works
> dfxyz[ , -"y"]
Error in -"y" : invalid argument to unary operator
This next mechanism also works and us especially useful on dataframes
with lots of columns:
dfxyz[ , -grep("y", names(dfxyz))]
But you need to be careful to make sure you know which columns will
match and its good practice to test the grepping expression first:
> grep("y", names(dfxyz))
[1] 2
If you only wanted to remove "y" and not "y2" you would need to add
qualifiers to the pattern.
Thanks, John rm(dfxyz,dfxz,dfxy) # create the data frame. dfxyz <- data.frame(x=1:10,y=11:20,z=factor(c(rep(0,5),rep(1,5)))) dfxyz names(dfxyz) # try to drop y column # does not work, does not produce error message dfxz <- dfxyz[,-(dfxyz$y)]
Well, dfxyz$y does evaluate to a numeric vector with values 11:20 and there were no columns in that range. So it behaved as documented. You asked for the dataframe without some non-existent (numbered) columns and it obliged.
dfxz # try to drop z column # does not work, produces error message: # In Ops.factor(df$z) : - not meaningful for factors dfxy <- dfxyz[,-dfxyz$z]
Right, you cannot subtract (or negate) factors. As Phil suggests, subset()-ting is often safer.
David.