Please, I wonder if someone knows how to add the
less than or equal to symbol in the plot generated by the code below:
var1<-c('age <= 3','age <= 7','age <= 10','age <= 11','age <= 20','age <=
25','age <= 30','age <= 45','age <= 50','age < 55','age >= 55')
var2<-c(3.8,5.4,3.7,3.8,5.9,6.4,7.2,8.4,10.5,1.3,0.7)
table1<-data.frame(var1, var2)
plot(x=table1$var2,y=1:11,xlim=c(0,20),pch=20)
text(x=table1$var2,y=1:11,table1$var1,pos=4)
title(x=15,y=5,expression("how to substitute the < = with the " <=
"symbol"),font=5)
Please, note that the data must come from a table (not manually fed in a
text command)
I received help yesterday and learned a fix using
\u2264, eval, parse, and sprintf? but the symbols generated by this fix are
not exported to an .EPS file
Kind regards,
Victor Faria Seabra, MD
Please, need help with a plot
5 messages · Ben Bolker, David Winsemius, Victor F Seabra +1 more
Victor F Seabra <vseabra <at> uol.com.br> writes:
Please, I wonder if someone knows how to add the
less than or equal to symbol in the plot generated by the code below:
var1<-c('age <= 3','age <= 7','age <= 10','age <= 11','age <= 20','age <=
25','age <= 30','age <= 45','age <= 50','age < 55','age >= 55')
var2<-c(3.8,5.4,3.7,3.8,5.9,6.4,7.2,8.4,10.5,1.3,0.7)
table1<-data.frame(var1, var2)
plot(x=table1$var2,y=1:11,xlim=c(0,20),pch=20)
text(x=table1$var2,y=1:11,table1$var1,pos=4)
title(x=15,y=5,expression("how to substitute the < = with the " <=
"symbol"),font=5)
Please, note that the data must come from a table (not manually fed in a
text command)
I received help yesterday and learned a fix using
\u2264, eval, parse, and sprintf? but the symbols generated by this fix are
not exported to an .EPS file
Kind regards,
This is a little bit more 'magic' than I would like, but seems
to work. Perhaps someone else can suggest a cleaner solution.
ages <- gsub("[^0-9]+","",table1$var1)
rel <- gsub("age\\s*([=<>]+)\\s*[0-9]+","\\1",table1$var1,perl=TRUE)
with(table1,plot(var2,1:11,xlim=c(0,20),pch=20))
invisible(with(table1,
mapply(function(x,y,a,r) {
text(x=x,y=y,
switch(r,
`<=`=bquote(age <= .(a)),
`<`=bquote(age < .(a)),
`>=`=bquote(age >= .(a))),
pos=4)},
var2,1:11,ages,rel)))
On Jan 2, 2011, at 1:15 PM, Ben Bolker wrote:
Victor F Seabra <vseabra <at> uol.com.br> writes:
Please, I wonder if someone knows how to add the
less than or equal to symbol in the plot generated by the code
below:
var1<-c('age <= 3','age <= 7','age <= 10','age <= 11','age <=
20','age <=
25','age <= 30','age <= 45','age <= 50','age < 55','age >= 55')
var2<-c(3.8,5.4,3.7,3.8,5.9,6.4,7.2,8.4,10.5,1.3,0.7)
table1<-data.frame(var1, var2)
plot(x=table1$var2,y=1:11,xlim=c(0,20),pch=20)
text(x=table1$var2,y=1:11,table1$var1,pos=4)
title(x=15,y=5,expression("how to substitute the < = with the
" <=
"symbol"),font=5)
Please, note that the data must come from a table (not manually
fed in a
text command)
I received help yesterday and learned a fix using
\u2264, eval, parse, and sprintf? but the symbols generated by
this fix are
not exported to an .EPS file
Kind regards,
This is a little bit more 'magic' than I would like, but seems to work. Perhaps someone else can suggest a cleaner solution.
Here's the best I could come up with but will admit that there were
many failed attempts before success:
expr.vec <- as.expression(parse(text=table1$var1))
plot(x=table1$var2 ,y=1:11, xlim=c(0,20), pch=20)
text(x=table1$var2, y=1:11, labels=expr.vec, pos=4)
title(x=15, y=5, expression("Yet another way to process strings with
operators like '<=' )
(The title expression works on my machine, but perhaps not on the OP's
machine, given differences in encoding that have so far been exhibited.)
ages <- gsub("[^0-9]+","",table1$var1)
rel <- gsub("age\\s*([=<>]+)\\s*[0-9]+","\\1",table1$var1,perl=TRUE)
with(table1,plot(var2,1:11,xlim=c(0,20),pch=20))
invisible(with(table1,
mapply(function(x,y,a,r) {
text(x=x,y=y,
switch(r,
`<=`=bquote(age <= .(a)),
`<`=bquote(age < .(a)),
`>=`=bquote(age >= .(a))),
pos=4)},
var2,1:11,ages,rel)))
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD West Hartford, CT
although the code somehow didn't work on my Vista / R 2.8, it did work perfectly on a XP machine / R 2.10 I've been trying to fix this for days, Thank you very much for your help! ______________________________________________________________________
02/01/2011 19:30, David Winsemius < dwinsemius at comcast.net > wrote:
On Jan 2, 2011, at 1:15 PM, Ben Bolker wrote:
This is a little bit more 'magic' than I would like, but seems to work. Perhaps someone else can suggest a cleaner solution.
Here's the best I could come up with but will admit that there were
many failed attempts before success:
expr.vec <- as.expression(parse(text=table1$var1))
plot(x=table1$var2 ,y=1:11, xlim=c(0,20), pch=20)
text(x=table1$var2, y=1:11, labels=expr.vec, pos=4)
title(x=15, y=5, expression("Yet another way to process strings with
operators like '<=' )
(The title expression works on my machine, but perhaps not on the OP's
machine, given differences in encoding that have so far been exhibited.)
ages <- gsub("[^0-9]+","",table1$var1)
rel <- gsub("age\\s*([=<>]+)\\s*[0-9]+","\\1",table1$var1,perl=TRUE)
with(table1,plot(var2,1:11,xlim=c(0,20),pch=20))
invisible(with(table1,
mapply(function(x,y,a,r) {
text(x=x,y=y,
switch(r,
`<=`=bquote(age <= .(a)),
`<`=bquote(age < .(a)),
`>=`=bquote(age >= .(a))),
pos=4)},
var2,1:11,ages,rel)))
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD West Hartford, CT
On 03.01.2011 14:25, Victor F Seabra wrote:
although the code somehow didn't work on my Vista / R 2.8, it did work perfectly on a XP machine / R 2.10
An when you update both machines to a recent R-2.12.1 you will find how much more will work in the end! Uwe Ligges
I've been trying to fix this for days, Thank you very much for your help!
______________________________________________________________________
02/01/2011 19:30, David Winsemius< dwinsemius at comcast.net> wrote:
On Jan 2, 2011, at 1:15 PM, Ben Bolker wrote:
This is a little bit more 'magic' than I would like, but seems
to work. Perhaps someone else can suggest a cleaner solution.
Here's the best I could come up with but will admit that there were
many failed attempts before success:
expr.vec<- as.expression(parse(text=table1$var1))
plot(x=table1$var2 ,y=1:11, xlim=c(0,20), pch=20)
text(x=table1$var2, y=1:11, labels=expr.vec, pos=4)
title(x=15, y=5, expression("Yet another way to process strings with
operators like '<=' )
(The title expression works on my machine, but perhaps not on the OP's
machine, given differences in encoding that have so far been exhibited.)
ages<- gsub("[^0-9]+","",table1$var1)
rel<- gsub("age\\s*([=<>]+)\\s*[0-9]+","\\1",table1$var1,perl=TRUE)
with(table1,plot(var2,1:11,xlim=c(0,20),pch=20))
invisible(with(table1,
mapply(function(x,y,a,r) {
text(x=x,y=y,
switch(r,
`<=`=bquote(age<= .(a)),
`<`=bquote(age< .(a)),
`>=`=bquote(age>= .(a))),
pos=4)},
var2,1:11,ages,rel)))
______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.