read.zoo supports all the arguments that read.table supports including header=. From the read.zoo help file: ...: further arguments passed to 'read.table'. Regards.
On 7/7/06, Horace Tso <Horace.Tso at pgn.com> wrote:
Thanks Gabor. I figured out what went wrong. The culprit turns out to be
the headers in my data. read.zoo doesn't recognize column headers and
complains
Error in read.zoo("C:\\.......\\table.csv", :
index contains NAs
Or is there an option as in read.table(x, header=...) ?
After the header line is removed it works fine.
H.
"Gabor Grothendieck" <ggrothendieck at gmail.com> 7/7/2006 10:22 AM
Check out read.zoo in the zoo package. On 7/7/06, Horace Tso <Horace.Tso at pgn.com> wrote:
Dear list, I know this is really basic question but I just couldn't get
anything
to work. (I did a R site search with keywords "zoo" and "data frame"
but
the server timed out on me.) I have a time series which has the following (typical) format, DATE Open High Low Close Volume 01-JAN-2006 5.25 5.25 5.25 5.25 256 .... I read the data in from a csv file with read.csv() and it defaulted
to
a data frame which I thought is fine. Now I want to convert it to zoo
so
I did x <- zoo(my.df) which works just fine. But the Date column has been turned into a factor. Is there a way to make it into a Date. I've tried, x$Date <- as.Date(x$Date) but R complains that Error in fromchar(x) : character string is not in a standard unambiguous format Thanks in advance. Horace W. Tso
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