Hi all,
I have this code, but the marginal distribution plot doesn?t appear aligned
with the left plot.
I think could be something about layout or par() mar.
The code was programmed by me time ago.
Can anyone help me to get the marginal distribution on the center (more
higher centered)
id.txt
Could have this code:
05/01/2016;9335,200195
06/01/2016;9197,400391
07/01/2016;9059,299805
08/01/2016;8909,200195
11/01/2016;8886,099609
12/01/2016;8915,400391
13/01/2016;8934,5
14/01/2016;8787,700195
15/01/2016;8543,599609
18/01/2016;8469,299805
19/01/2016;8554,900391
20/01/2016;8281,400391
21/01/2016;8444,200195
22/01/2016;8722,900391
25/01/2016;8567,700195
26/01/2016;8692,5
27/01/2016;8741
g<-read.table("id.txt", col.names=c("Dateh","LAST"), sep=";", dec=",")
N=5000
B=24
ghy<-nrow(g)
r<-as.numeric(as.character(g$LAST[ghy]))
nf<-layout(matrix(c(1,1,1,1,2,2),1,6,byrow=TRUE))
par(mar=c(6,6,6,0.5))
A<-matrix(1:B,B,N);
sigma<-0.06;
mu<-0.00;
Z<-r*exp((mu-0.5*((sigma)^2)*A) +sigma*(sqrt(A))*matrix( rnorm(N*B,0,1), B,
N))
real1<-g$LAST[1:nrow(g)]
real2<-matrix(NA,nrow(g),N-1)
real<-cbind(real1,real2)
Po<-r*matrix(1,1,N);
Sim<-rbind(Po,Z)
Simulation<-rbind(real,Z)
par(mar=c(10,6,6,6))
matplot(Simulation,type="l",ylim=c(0,40000))
abline(h = 8000, lwd = 2, col = "black")
abline(h = 12000, lwd = 2, col = "black")
title("Dinamic Montecarlo Simulation 2 years ahead",font=4)
fhist<-hist(Simulation,plot=FALSE)
par(mar=c(6,0,6,6))
barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray")
grid()
title("Marginal Distribution",font=4)
rect(0, 0, 0, 0) # transparent
Plot MArginal distribution in the correct place
8 messages · Pedro páramo, Jim Lemon
Please, I'm trying to put the right plot higher and centered on the left values but I don't achive. I would appreciate so much your help El 6 jun. 2017 22:37, "Pedro p?ramo" <percentil101 at gmail.com> escribi?:
Hi all,
I have this code, but the marginal distribution plot doesn?t appear
aligned with the left plot.
I think could be something about layout or par() mar.
The code was programmed by me time ago.
Can anyone help me to get the marginal distribution on the center (more
higher centered)
id.txt
Could have this code:
05/01/2016;9335,200195
06/01/2016;9197,400391
07/01/2016;9059,299805
08/01/2016;8909,200195
11/01/2016;8886,099609
12/01/2016;8915,400391
13/01/2016;8934,5
14/01/2016;8787,700195
15/01/2016;8543,599609
18/01/2016;8469,299805
19/01/2016;8554,900391
20/01/2016;8281,400391
21/01/2016;8444,200195
22/01/2016;8722,900391
25/01/2016;8567,700195
26/01/2016;8692,5
27/01/2016;8741
g<-read.table("id.txt", col.names=c("Dateh","LAST"), sep=";", dec=",")
N=5000
B=24
ghy<-nrow(g)
r<-as.numeric(as.character(g$LAST[ghy]))
nf<-layout(matrix(c(1,1,1,1,2,2),1,6,byrow=TRUE))
par(mar=c(6,6,6,0.5))
A<-matrix(1:B,B,N);
sigma<-0.06;
mu<-0.00;
Z<-r*exp((mu-0.5*((sigma)^2)*A) +sigma*(sqrt(A))*matrix( rnorm(N*B,0,1),
B, N))
real1<-g$LAST[1:nrow(g)]
real2<-matrix(NA,nrow(g),N-1)
real<-cbind(real1,real2)
Po<-r*matrix(1,1,N);
Sim<-rbind(Po,Z)
Simulation<-rbind(real,Z)
par(mar=c(10,6,6,6))
matplot(Simulation,type="l",ylim=c(0,40000))
abline(h = 8000, lwd = 2, col = "black")
abline(h = 12000, lwd = 2, col = "black")
title("Dinamic Montecarlo Simulation 2 years ahead",font=4)
fhist<-hist(Simulation,plot=FALSE)
par(mar=c(6,0,6,6))
barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray")
grid()
title("Marginal Distribution",font=4)
rect(0, 0, 0, 0) # transparent
Hi Pedro, As a one-off, you just shove the coordinates around a bit: par(mar=c(11,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray", ylim=c(0,24)) However, I don't think that this plot illustrates quite what you think it does. Jim
On Wed, Jun 7, 2017 at 4:01 PM, Pedro p?ramo <percentil101 at gmail.com> wrote:
Please, I'm trying to put the right plot higher and centered on the left values but I don't achive. I would appreciate so much your help El 6 jun. 2017 22:37, "Pedro p?ramo" <percentil101 at gmail.com> escribi?:
Hi all,
I have this code, but the marginal distribution plot doesn?t appear
aligned with the left plot.
I think could be something about layout or par() mar.
The code was programmed by me time ago.
Can anyone help me to get the marginal distribution on the center (more
higher centered)
id.txt
Could have this code:
05/01/2016;9335,200195
06/01/2016;9197,400391
07/01/2016;9059,299805
08/01/2016;8909,200195
11/01/2016;8886,099609
12/01/2016;8915,400391
13/01/2016;8934,5
14/01/2016;8787,700195
15/01/2016;8543,599609
18/01/2016;8469,299805
19/01/2016;8554,900391
20/01/2016;8281,400391
21/01/2016;8444,200195
22/01/2016;8722,900391
25/01/2016;8567,700195
26/01/2016;8692,5
27/01/2016;8741
g<-read.table("id.txt", col.names=c("Dateh","LAST"), sep=";", dec=",")
N=5000
B=24
ghy<-nrow(g)
r<-as.numeric(as.character(g$LAST[ghy]))
nf<-layout(matrix(c(1,1,1,1,2,2),1,6,byrow=TRUE))
par(mar=c(6,6,6,0.5))
A<-matrix(1:B,B,N);
sigma<-0.06;
mu<-0.00;
Z<-r*exp((mu-0.5*((sigma)^2)*A) +sigma*(sqrt(A))*matrix( rnorm(N*B,0,1),
B, N))
real1<-g$LAST[1:nrow(g)]
real2<-matrix(NA,nrow(g),N-1)
real<-cbind(real1,real2)
Po<-r*matrix(1,1,N);
Sim<-rbind(Po,Z)
Simulation<-rbind(real,Z)
par(mar=c(10,6,6,6))
matplot(Simulation,type="l",ylim=c(0,40000))
abline(h = 8000, lwd = 2, col = "black")
abline(h = 12000, lwd = 2, col = "black")
title("Dinamic Montecarlo Simulation 2 years ahead",font=4)
fhist<-hist(Simulation,plot=FALSE)
par(mar=c(6,0,6,6))
barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray")
grid()
title("Marginal Distribution",font=4)
rect(0, 0, 0, 0) # transparent
[[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
1 day later
Many thanks Jim. What I,m trying to show with the fhist plot is the empirical distribution of the values of the left plot simulation. You say: However, I don't think that this plot illustrates quite what you think it does. Can you give me a clue to try to illustrate better if it is not showing what I believe it shows a better way to show it? Many thanks in advance. El 7 jun. 2017 12:08, "Jim Lemon" <drjimlemon at gmail.com> escribi?: Hi Pedro, As a one-off, you just shove the coordinates around a bit: par(mar=c(11,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray", ylim=c(0,24)) However, I don't think that this plot illustrates quite what you think it does. Jim
On Wed, Jun 7, 2017 at 4:01 PM, Pedro p?ramo <percentil101 at gmail.com> wrote:
Please, I'm trying to put the right plot higher and centered on the left values but I don't achive. I would appreciate so much your help El 6 jun. 2017 22:37, "Pedro p?ramo" <percentil101 at gmail.com> escribi?:
Hi all,
I have this code, but the marginal distribution plot doesn?t appear
aligned with the left plot.
I think could be something about layout or par() mar.
The code was programmed by me time ago.
Can anyone help me to get the marginal distribution on the center (more
higher centered)
id.txt
Could have this code:
05/01/2016;9335,200195
06/01/2016;9197,400391
07/01/2016;9059,299805
08/01/2016;8909,200195
11/01/2016;8886,099609
12/01/2016;8915,400391
13/01/2016;8934,5
14/01/2016;8787,700195
15/01/2016;8543,599609
18/01/2016;8469,299805
19/01/2016;8554,900391
20/01/2016;8281,400391
21/01/2016;8444,200195
22/01/2016;8722,900391
25/01/2016;8567,700195
26/01/2016;8692,5
27/01/2016;8741
g<-read.table("id.txt", col.names=c("Dateh","LAST"), sep=";", dec=",")
N=5000
B=24
ghy<-nrow(g)
r<-as.numeric(as.character(g$LAST[ghy]))
nf<-layout(matrix(c(1,1,1,1,2,2),1,6,byrow=TRUE))
par(mar=c(6,6,6,0.5))
A<-matrix(1:B,B,N);
sigma<-0.06;
mu<-0.00;
Z<-r*exp((mu-0.5*((sigma)^2)*A) +sigma*(sqrt(A))*matrix( rnorm(N*B,0,1),
B, N))
real1<-g$LAST[1:nrow(g)]
real2<-matrix(NA,nrow(g),N-1)
real<-cbind(real1,real2)
Po<-r*matrix(1,1,N);
Sim<-rbind(Po,Z)
Simulation<-rbind(real,Z)
par(mar=c(10,6,6,6))
matplot(Simulation,type="l",ylim=c(0,40000))
abline(h = 8000, lwd = 2, col = "black")
abline(h = 12000, lwd = 2, col = "black")
title("Dinamic Montecarlo Simulation 2 years ahead",font=4)
fhist<-hist(Simulation,plot=FALSE)
par(mar=c(6,0,6,6))
barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray")
grid()
title("Marginal Distribution",font=4)
rect(0, 0, 0, 0) # transparent
[[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/
posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
5 days later
Please can you send me some orientation? Many thanks in advance. Only if posible one book o similar example to understand why it is not what I try. El 8 jun. 2017 7:50 PM, "Pedro p?ramo" <percentil101 at gmail.com> escribi?:
Many thanks Jim. What I,m trying to show with the fhist plot is the empirical distribution of the values of the left plot simulation. You say: However, I don't think that this plot illustrates quite what you think it does. Can you give me a clue to try to illustrate better if it is not showing what I believe it shows a better way to show it? Many thanks in advance. El 7 jun. 2017 12:08, "Jim Lemon" <drjimlemon at gmail.com> escribi?: Hi Pedro, As a one-off, you just shove the coordinates around a bit: par(mar=c(11,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray", ylim=c(0,24)) However, I don't think that this plot illustrates quite what you think it does. Jim On Wed, Jun 7, 2017 at 4:01 PM, Pedro p?ramo <percentil101 at gmail.com> wrote:
Please, I'm trying to put the right plot higher and centered on the left values but I don't achive. I would appreciate so much your help El 6 jun. 2017 22:37, "Pedro p?ramo" <percentil101 at gmail.com> escribi?:
Hi all,
I have this code, but the marginal distribution plot doesn?t appear
aligned with the left plot.
I think could be something about layout or par() mar.
The code was programmed by me time ago.
Can anyone help me to get the marginal distribution on the center (more
higher centered)
id.txt
Could have this code:
05/01/2016;9335,200195
06/01/2016;9197,400391
07/01/2016;9059,299805
08/01/2016;8909,200195
11/01/2016;8886,099609
12/01/2016;8915,400391
13/01/2016;8934,5
14/01/2016;8787,700195
15/01/2016;8543,599609
18/01/2016;8469,299805
19/01/2016;8554,900391
20/01/2016;8281,400391
21/01/2016;8444,200195
22/01/2016;8722,900391
25/01/2016;8567,700195
26/01/2016;8692,5
27/01/2016;8741
g<-read.table("id.txt", col.names=c("Dateh","LAST"), sep=";", dec=",")
N=5000
B=24
ghy<-nrow(g)
r<-as.numeric(as.character(g$LAST[ghy]))
nf<-layout(matrix(c(1,1,1,1,2,2),1,6,byrow=TRUE))
par(mar=c(6,6,6,0.5))
A<-matrix(1:B,B,N);
sigma<-0.06;
mu<-0.00;
Z<-r*exp((mu-0.5*((sigma)^2)*A) +sigma*(sqrt(A))*matrix(
rnorm(N*B,0,1),
B, N))
real1<-g$LAST[1:nrow(g)]
real2<-matrix(NA,nrow(g),N-1)
real<-cbind(real1,real2)
Po<-r*matrix(1,1,N);
Sim<-rbind(Po,Z)
Simulation<-rbind(real,Z)
par(mar=c(10,6,6,6))
matplot(Simulation,type="l",ylim=c(0,40000))
abline(h = 8000, lwd = 2, col = "black")
abline(h = 12000, lwd = 2, col = "black")
title("Dinamic Montecarlo Simulation 2 years ahead",font=4)
fhist<-hist(Simulation,plot=FALSE)
par(mar=c(6,0,6,6))
barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray")
grid()
title("Marginal Distribution",font=4)
rect(0, 0, 0, 0) # transparent
[[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posti
ng-guide.html
and provide commented, minimal, self-contained, reproducible code.
Hi Pedro, If you keep that same margins for the second plot: par(mar=c(10,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray") it looks reasonably well aligned to me. Because you are plotting the counts of the values in Simulation, the ordinate (vertical axis) of the bar plot is in quite different units from that of the plot on the left side. Jim
On Wed, Jun 14, 2017 at 5:33 PM, Pedro p?ramo <percentil101 at gmail.com> wrote:
Please can you send me some orientation? Many thanks in advance. Only if posible one book o similar example to understand why it is not what I try. El 8 jun. 2017 7:50 PM, "Pedro p?ramo" <percentil101 at gmail.com> escribi?:
Many thanks Jim. What I,m trying to show with the fhist plot is the empirical distribution of the values of the left plot simulation. You say: However, I don't think that this plot illustrates quite what you think it does. Can you give me a clue to try to illustrate better if it is not showing what I believe it shows a better way to show it? Many thanks in advance. El 7 jun. 2017 12:08, "Jim Lemon" <drjimlemon at gmail.com> escribi?: Hi Pedro, As a one-off, you just shove the coordinates around a bit: par(mar=c(11,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray", ylim=c(0,24)) However, I don't think that this plot illustrates quite what you think it does. Jim On Wed, Jun 7, 2017 at 4:01 PM, Pedro p?ramo <percentil101 at gmail.com> wrote:
Please, I'm trying to put the right plot higher and centered on the left values but I don't achive. I would appreciate so much your help El 6 jun. 2017 22:37, "Pedro p?ramo" <percentil101 at gmail.com> escribi?:
Hi all,
I have this code, but the marginal distribution plot doesn?t appear
aligned with the left plot.
I think could be something about layout or par() mar.
The code was programmed by me time ago.
Can anyone help me to get the marginal distribution on the center (more
higher centered)
id.txt
Could have this code:
05/01/2016;9335,200195
06/01/2016;9197,400391
07/01/2016;9059,299805
08/01/2016;8909,200195
11/01/2016;8886,099609
12/01/2016;8915,400391
13/01/2016;8934,5
14/01/2016;8787,700195
15/01/2016;8543,599609
18/01/2016;8469,299805
19/01/2016;8554,900391
20/01/2016;8281,400391
21/01/2016;8444,200195
22/01/2016;8722,900391
25/01/2016;8567,700195
26/01/2016;8692,5
27/01/2016;8741
g<-read.table("id.txt", col.names=c("Dateh","LAST"), sep=";", dec=",")
N=5000
B=24
ghy<-nrow(g)
r<-as.numeric(as.character(g$LAST[ghy]))
nf<-layout(matrix(c(1,1,1,1,2,2),1,6,byrow=TRUE))
par(mar=c(6,6,6,0.5))
A<-matrix(1:B,B,N);
sigma<-0.06;
mu<-0.00;
Z<-r*exp((mu-0.5*((sigma)^2)*A) +sigma*(sqrt(A))*matrix(
rnorm(N*B,0,1),
B, N))
real1<-g$LAST[1:nrow(g)]
real2<-matrix(NA,nrow(g),N-1)
real<-cbind(real1,real2)
Po<-r*matrix(1,1,N);
Sim<-rbind(Po,Z)
Simulation<-rbind(real,Z)
par(mar=c(10,6,6,6))
matplot(Simulation,type="l",ylim=c(0,40000))
abline(h = 8000, lwd = 2, col = "black")
abline(h = 12000, lwd = 2, col = "black")
title("Dinamic Montecarlo Simulation 2 years ahead",font=4)
fhist<-hist(Simulation,plot=FALSE)
par(mar=c(6,0,6,6))
barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray")
grid()
title("Marginal Distribution",font=4)
rect(0, 0, 0, 0) # transparent
[[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
3 days later
Can you suggest a plot on the right side so that the right plot has the same units of left plot and reflect the counts of the number of time the values repeat, something like the empirical distribution? 2017-06-14 12:30 GMT+02:00 Jim Lemon <drjimlemon at gmail.com>:
Hi Pedro, If you keep that same margins for the second plot: par(mar=c(10,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray") it looks reasonably well aligned to me. Because you are plotting the counts of the values in Simulation, the ordinate (vertical axis) of the bar plot is in quite different units from that of the plot on the left side. Jim On Wed, Jun 14, 2017 at 5:33 PM, Pedro p?ramo <percentil101 at gmail.com> wrote:
Please can you send me some orientation? Many thanks in advance. Only if posible one book o similar example to understand why it is not
what
I try. El 8 jun. 2017 7:50 PM, "Pedro p?ramo" <percentil101 at gmail.com>
escribi?:
Many thanks Jim. What I,m trying to show with the fhist plot is the empirical
distribution
of the values of the left plot simulation. You say: However, I don't think that this plot illustrates quite what you think
it
does. Can you give me a clue to try to illustrate better if it is not showing what I believe it shows a better way to show it? Many thanks in advance. El 7 jun. 2017 12:08, "Jim Lemon" <drjimlemon at gmail.com> escribi?: Hi Pedro, As a one-off, you just shove the coordinates around a bit: par(mar=c(11,0,6,6)) barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray", ylim=c(0,24)) However, I don't think that this plot illustrates quite what you think
it
does. Jim On Wed, Jun 7, 2017 at 4:01 PM, Pedro p?ramo <percentil101 at gmail.com> wrote:
Please, I'm trying to put the right plot higher and centered on the
left
values but I don't achive. I would appreciate so much your help El 6 jun. 2017 22:37, "Pedro p?ramo" <percentil101 at gmail.com>
escribi?:
Hi all, I have this code, but the marginal distribution plot doesn?t appear aligned with the left plot. I think could be something about layout or par() mar. The code was programmed by me time ago. Can anyone help me to get the marginal distribution on the center
(more
higher centered)
id.txt
Could have this code:
05/01/2016;9335,200195
06/01/2016;9197,400391
07/01/2016;9059,299805
08/01/2016;8909,200195
11/01/2016;8886,099609
12/01/2016;8915,400391
13/01/2016;8934,5
14/01/2016;8787,700195
15/01/2016;8543,599609
18/01/2016;8469,299805
19/01/2016;8554,900391
20/01/2016;8281,400391
21/01/2016;8444,200195
22/01/2016;8722,900391
25/01/2016;8567,700195
26/01/2016;8692,5
27/01/2016;8741
g<-read.table("id.txt", col.names=c("Dateh","LAST"), sep=";",
dec=",")
N=5000
B=24
ghy<-nrow(g)
r<-as.numeric(as.character(g$LAST[ghy]))
nf<-layout(matrix(c(1,1,1,1,2,2),1,6,byrow=TRUE))
par(mar=c(6,6,6,0.5))
A<-matrix(1:B,B,N);
sigma<-0.06;
mu<-0.00;
Z<-r*exp((mu-0.5*((sigma)^2)*A) +sigma*(sqrt(A))*matrix(
rnorm(N*B,0,1),
B, N))
real1<-g$LAST[1:nrow(g)]
real2<-matrix(NA,nrow(g),N-1)
real<-cbind(real1,real2)
Po<-r*matrix(1,1,N);
Sim<-rbind(Po,Z)
Simulation<-rbind(real,Z)
par(mar=c(10,6,6,6))
matplot(Simulation,type="l",ylim=c(0,40000))
abline(h = 8000, lwd = 2, col = "black")
abline(h = 12000, lwd = 2, col = "black")
title("Dinamic Montecarlo Simulation 2 years ahead",font=4)
fhist<-hist(Simulation,plot=FALSE)
par(mar=c(6,0,6,6))
barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray")
grid()
title("Marginal Distribution",font=4)
rect(0, 0, 0, 0) # transparent
[[alternative HTML version deleted]]
______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
As you have categorized the original values, they are different from
the originals. You could include the categories like this, with a bit
of fiddling the margins and y limits for the right hand plot:
x11(width=10)
nf<-layout(matrix(c(1,1,1,1,2,2),1,6,byrow=TRUE))
par(mar=c(10,6,6,6))
matplot(Simulation,type="l",ylim=c(0,40000))
abline(h = 8000, lwd = 2, col = "black")
abline(h = 12000, lwd = 2, col = "black")
title("Dinamic Montecarlo Simulation 2 years ahead",font=4)
fhist<-hist(Simulation,plot=FALSE)
par(mar=c(10,6,6,6))
barplot(fhist$counts,axes=FALSE, space=0,horiz=TRUE,col="lightgray",
names.arg=paste(fhist$breaks[1:23],fhist$breaks[2:24],sep="-"),
las=2,ylim=c(-3,40))
grid()
title("Marginal Distribution",font=4)
Jim
On Sun, Jun 18, 2017 at 3:51 AM, Pedro p?ramo <percentil101 at gmail.com> wrote:
Can you suggest a plot on the right side so that the right plot has the same units of left plot and reflect the counts of the number of time the values repeat, something like the empirical distribution?