I am lousy at simple regex and I have not found a solution to a simple problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)", "ALP (max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy = c("mat harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but either I am misunderstanding the function or don't know how to escape a "(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated
Thanks
John Kane
Kingston ON Canada
____________________________________________________________
FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop!
Splitting a character vector.
11 messages · Rui Barradas, John Kane, Jeff Newmiller +1 more
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must be escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a solution to a simple problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)", "ALP (max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy = c("mat harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but either I am misunderstanding the function or don't know how to escape a "(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated
Thanks
John Kane
Kingston ON Canada
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Thanks Rui It works perfectly so far on the test and real data. The annoying thing is that I had tried , or thought I'd tried the open.par format and keep getting an error. It looks like I had failed to add the '''', in the term. What is it doing? John Kane Kingston ON Canada
-----Original Message-----
From: ruipbarradas at sapo.pt
Sent: Sat, 07 Jul 2012 22:55:41 +0100
To: jrkrideau at inbox.com
Subject: Re: [R] Splitting a character vector.
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must be escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a solution to a simple
problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)", "ALP
(max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy = c("mat
harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to escape a
"(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated
Thanks
John Kane
Kingston ON Canada
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
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Hello, Sorry, but I don't understand, you're asking about 4 single quotes, the double quotes in open.par are just opening and closing the pattern, a character string. Rui Barradas Em 07-07-2012 23:03, John Kane escreveu:
Thanks Rui It works perfectly so far on the test and real data. The annoying thing is that I had tried , or thought I'd tried the open.par format and keep getting an error. It looks like I had failed to add the '''', in the term. What is it doing? John Kane Kingston ON Canada
-----Original Message-----
From: ruipbarradas at sapo.pt
Sent: Sat, 07 Jul 2012 22:55:41 +0100
To: jrkrideau at inbox.com
Subject: Re: [R] Splitting a character vector.
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must be escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a solution to a simple
problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)", "ALP
(max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy = c("mat
harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to escape a
"(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated
Thanks
John Kane
Kingston ON Canada
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! Check it out at http://www.inbox.com/marineaquarium
Just to clarify, the regex engine wants to see a \ before the ( if it is to treat it as an ordinary character. However, the source code interpreter also treats \ as an escape character. In order to get a \ into the string, you have to escape it. So it takes two \ characters in source code to obtain one \ character in memory where the regex code can "see" it.
---------------------------------------------------------------------------
Jeff Newmiller The ..... ..... Go Live...
DCN:<jdnewmil at dcn.davis.ca.us> Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries O.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#. rocks...1k
---------------------------------------------------------------------------
Sent from my phone. Please excuse my brevity.
Rui Barradas <ruipbarradas at sapo.pt> wrote:
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must be
escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a solution to a
simple problem.
I have a vector with some character values that I want to split. Sample data dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)",
"ALP (max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy = c("mat
harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to escape a
"(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated Thanks John Kane Kingston ON Canada
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas
on your desktop!
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
No sorry Rui, In the expression result <- strsplit(sub(close.par, "", dd1), open.par) there is close.par, ''", open.par I probably am just blind but I don't understand what it is doing. John Kane Kingston ON Canada
-----Original Message----- From: ruipbarradas at sapo.pt Sent: Sat, 07 Jul 2012 23:08:19 +0100 To: jrkrideau at inbox.com Subject: Re: [R] Splitting a character vector. Hello, Sorry, but I don't understand, you're asking about 4 single quotes, the double quotes in open.par are just opening and closing the pattern, a character string. Rui Barradas Em 07-07-2012 23:03, John Kane escreveu:
Thanks Rui It works perfectly so far on the test and real data. The annoying thing is that I had tried , or thought I'd tried the open.par format and keep getting an error. It looks like I had failed to add the '''', in the term. What is it doing? John Kane Kingston ON Canada
-----Original Message-----
From: ruipbarradas at sapo.pt
Sent: Sat, 07 Jul 2012 22:55:41 +0100
To: jrkrideau at inbox.com
Subject: Re: [R] Splitting a character vector.
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must be
escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a solution to a simple
problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)", "ALP
(max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy = c("mat
harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to escape
a
"(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated
Thanks
John Kane
Kingston ON Canada
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! Check it out at http://www.inbox.com/marineaquarium
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop!
Thanks Jeff. I actually had that figured out after a good hour of pounding my head against the wall but I still could not seem to get the syntax correct. I think I misunderstand strpsplt() just enough to keep making dumb mistakes. John Kane Kingston ON Canada
-----Original Message-----
From: jdnewmil at dcn.davis.ca.us
Sent: Sat, 07 Jul 2012 15:12:16 -0700
To: ruipbarradas at sapo.pt, jrkrideau at inbox.com
Subject: Re: [R] Splitting a character vector.
Just to clarify, the regex engine wants to see a \ before the ( if it is
to treat it as an ordinary character. However, the source code
interpreter also treats \ as an escape character. In order to get a \
into the string, you have to escape it. So it takes two \ characters in
source code to obtain one \ character in memory where the regex code can
"see" it.
---------------------------------------------------------------------------
Jeff Newmiller The ..... ..... Go
Live...
DCN:<jdnewmil at dcn.davis.ca.us> Basics: ##.#. ##.#. Live
Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries O.O#. #.O#. with
/Software/Embedded Controllers) .OO#. .OO#.
rocks...1k
---------------------------------------------------------------------------
Sent from my phone. Please excuse my brevity.
Rui Barradas <ruipbarradas at sapo.pt> wrote:
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must be
escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a solution to a
simple problem.
I have a vector with some character values that I want to split. Sample data dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)",
"ALP (max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy = c("mat
harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to escape a
"(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated Thanks John Kane Kingston ON Canada
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas
on your desktop!
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
____________________________________________________________ FREE 3D EARTH SCREENSAVER - Watch the Earth right on your desktop!
It's an empty character string, meant to substitute nothing for close.par, to get rid of it. Rui Barradas Em 07-07-2012 23:17, John Kane escreveu:
No sorry Rui, In the expression result <- strsplit(sub(close.par, "", dd1), open.par) there is close.par, ''", open.par I probably am just blind but I don't understand what it is doing. John Kane Kingston ON Canada
-----Original Message----- From: ruipbarradas at sapo.pt Sent: Sat, 07 Jul 2012 23:08:19 +0100 To: jrkrideau at inbox.com Subject: Re: [R] Splitting a character vector. Hello, Sorry, but I don't understand, you're asking about 4 single quotes, the double quotes in open.par are just opening and closing the pattern, a character string. Rui Barradas Em 07-07-2012 23:03, John Kane escreveu:
Thanks Rui It works perfectly so far on the test and real data. The annoying thing is that I had tried , or thought I'd tried the open.par format and keep getting an error. It looks like I had failed to add the '''', in the term. What is it doing? John Kane Kingston ON Canada
-----Original Message-----
From: ruipbarradas at sapo.pt
Sent: Sat, 07 Jul 2012 22:55:41 +0100
To: jrkrideau at inbox.com
Subject: Re: [R] Splitting a character vector.
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must be
escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a solution to a simple
problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)", "ALP
(max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy = c("mat
harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to escape
a
"(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated
Thanks
John Kane
Kingston ON Canada
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! Check it out at http://www.inbox.com/marineaquarium
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! Check it out at http://www.inbox.com/marineaquarium
How totaly obvious once you tell me! I would have spend days trying to figure it out. I think I have a total mental block on regex and their derivatives. Thanks very much. John Kane Kingston ON Canada
-----Original Message----- From: ruipbarradas at sapo.pt Sent: Sat, 07 Jul 2012 23:21:19 +0100 To: jrkrideau at inbox.com Subject: Re: [R] Splitting a character vector. It's an empty character string, meant to substitute nothing for close.par, to get rid of it. Rui Barradas Em 07-07-2012 23:17, John Kane escreveu:
No sorry Rui, In the expression result <- strsplit(sub(close.par, "", dd1), open.par) there is close.par, ''", open.par I probably am just blind but I don't understand what it is doing. John Kane Kingston ON Canada
-----Original Message----- From: ruipbarradas at sapo.pt Sent: Sat, 07 Jul 2012 23:08:19 +0100 To: jrkrideau at inbox.com Subject: Re: [R] Splitting a character vector. Hello, Sorry, but I don't understand, you're asking about 4 single quotes, the double quotes in open.par are just opening and closing the pattern, a character string. Rui Barradas Em 07-07-2012 23:03, John Kane escreveu:
Thanks Rui It works perfectly so far on the test and real data. The annoying thing is that I had tried , or thought I'd tried the open.par format and keep getting an error. It looks like I had failed to add the '''', in the term. What is it doing? John Kane Kingston ON Canada
-----Original Message-----
From: ruipbarradas at sapo.pt
Sent: Sat, 07 Jul 2012 22:55:41 +0100
To: jrkrideau at inbox.com
Subject: Re: [R] Splitting a character vector.
Hello,
Try the following.
open.par <- " \\(" # with a blank before '('
close.par <- "\\)"
result <- strsplit(sub(close.par, "", dd1), open.par)
Why the two '\\'? Because '(' is a meta-character so it must be
escaped.
But '\' is a meta character so it must also be escaped.
Then choose the right way to separate the two, maybe something like
ix <- rep(c(TRUE, FALSE), length(result))
unlist(result)[ix]
unlist(result)[!ix]
Hope this helps,
Rui Barradas
Em 07-07-2012 22:37, John Kane escreveu:
I am lousy at simple regex and I have not found a solution to a
simple
problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)",
"ALP
(max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy =
c("mat
harry", "jim bob" , "joe blow", "max jack"))
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to
escape
a
"(" properly in an effort to at least get "XXY" "(mat harry)"
Any pointers would be appreciated
Thanks
John Kane
Kingston ON Canada
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
____________________________________________________________ FREE 3D MARINE AQUARIUM SCREENSAVER - Watch dolphins, sharks & orcas on your desktop! Check it out at http://www.inbox.com/marineaquarium
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On Jul 7, 2012, at 5:37 PM, John Kane wrote:
I am lousy at simple regex and I have not found a solution to a
simple problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)",
"ALP (max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy =
c("mat harry", "jim bob" , "joe blow", "max jack"))
data.frame(xx=sub("(\\s\\(.+$)", "", dd1),
yy=sub("(.+)(\\s\\()(.+)(\\)$)", "\\3", dd1) )
xx yy
1 XXY mat harry
2 XXY jim bob
3 CAMP joe blow
4 ALP max jack
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to
escape a "(" properly in an effort to at least get "XXY" "(mat
harry)"
David Winsemius, MD Heritage Laboratories West Hartford, CT
Works perfectly. Thank you very much indeed. John Kane Kingston ON Canada
-----Original Message----- From: dwinsemius at comcast.net Sent: Sat, 7 Jul 2012 21:45:58 -0400 To: jrkrideau at inbox.com Subject: Re: [R] Splitting a character vector. On Jul 7, 2012, at 5:37 PM, John Kane wrote:
I am lousy at simple regex and I have not found a solution to a
simple problem.
I have a vector with some character values that I want to split.
Sample data
dd1 <- c( "XXY (mat harry)","XXY (jim bob)", "CAMP (joe blow)",
"ALP (max jack)")
Desired result
dd2 <- data.frame( xx = c("XXY", "XXY", "CAMP", "ALP"), yy =
c("mat harry", "jim bob" , "joe blow", "max jack"))
data.frame(xx=sub("(\\s\\(.+$)", "", dd1),
yy=sub("(.+)(\\s\\()(.+)(\\)$)", "\\3", dd1) )
xx yy
1 XXY mat harry
2 XXY jim bob
3 CAMP joe blow
4 ALP max jack
I thought I should be able to split the characters with strsplit but
either I am misunderstanding the function or don't know how to
escape a "(" properly in an effort to at least get "XXY" "(mat
harry)"
David Winsemius, MD Heritage Laboratories West Hartford, CT
____________________________________________________________ FREE 3D EARTH SCREENSAVER - Watch the Earth right on your desktop!