Thank you!
```
new_out <- new[ , "ID" != names( new ) ]
new[names(new) != "ID"]
```
worked as wanted, `new[-match("ID"), names(new)]` gave the error:
`Error in match("ID") : argument "table" is missing, with no default`.
Cheers
On Fri, Sep 24, 2021 at 7:33 PM Rui Barradas <ruipbarradas at sapo.pt> wrote:
Hello,
Like this?
mtcars[names(mtcars) != "mpg"]
Hope this helps,
Rui Barradas
?s 15:09 de 24/09/21, Luigi Marongiu escreveu:
Hello,
this is a very simple question but...
what is the vector alternative to `subset(dataframe, select = - column)`?
I tried with:
```
Error in `[.data.frame`(new, -ID) : object 'ID' not found
Error in -"ID" : invalid argument to unary operator
Error in -"ID" : invalid argument to unary operator
Error: unexpected '[' in "x = new[-["
```
Thank you