Access comonents in lists of lists

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lapply(lst, function(x) return(x[[2]]))
Dear R users,I have a list of equally structured lists, how can I access e.g.
all 2nd compontents in those sub-lists?An example:lst <-
list(rep(list(1:3),3), rep(list(4:6),3))> lst[[1]][[1]][[1]][1] 1 2
3[[1]][[2]][1] 1 2 3[[1]][[3]][1] 1 2 3[[2]][[2]][[1]][1] 4 5 6[[2]][[2]][1]
4 5 6[[2]][[3]][1] 4 5 6What I want to get are all second sub-lists, in this
case:[[1]][[2]][1] 1 2 3and[[2]][[2]][1] 4 5 6many thanksBj?rn

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Dear R users,I have a list of equally structured lists, how can I access e.g.
all 2nd compontents in those sub-lists?An example:lst <-
list(rep(list(1:3),3), rep(list(4:6),3))> lst[[1]][[1]][[1]][1] 1 2
3[[1]][[2]][1] 1 2 3[[1]][[3]][1] 1 2 3[[2]][[2]][[1]][1] 4 5 6[[2]][[2]][1]
4 5 6[[2]][[3]][1] 4 5 6What I want to get are all second sub-lists, in this
case:[[1]][[2]][1] 1 2 3and[[2]][[2]][1] 4 5 6
Your email was/is a bit hard to read .... but if I understand correctly, 
what
you want is

     lst2 <- lapply(lst,function(x){x[[2]]})

See ?lapply.  Also associated functions like tapply() and sapply(). Very
useful gadgets.  And if you really get hooked on such functionality, you
might want to have a look at the "plyr" package.

     cheers,

         Rolf Turner