try this:
vec1 <- c(4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81) vec2 <- c (1,2,3,4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66) vec3 <- c (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,52) intersect(vec1,intersect(vec2, vec3))
[1] 4 5 6 7 8 9 10 11 12 52
On Sat, Oct 1, 2011 at 2:00 AM, Chris Conner <connerpharmd at yahoo.com> wrote:
Help-Rs, I've got three vectors representing participants: vec1 <- c(4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81) vec2 <- c (1,2,3,4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66) vec3 <- c (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,52) I'd like to return a vector that contains only the values that are shared across ALL THREE vectors. So the statement would return a vector that looked like this: 4,5,6,7,8,9,10,11,12,52 For some reason I initially thought that a cbind and a unique() would handle it, but then common sense sunk in.? I think the sleep deprivation is starting to take it's toll.? I've got to believe that there is a simple solution to this dilema. Thanks in adance for any help! C ? ? ? ?[[alternative HTML version deleted]]
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