Seems irrelevant to me. You can export the data to separate files directly from the matrix using matrix indexing. i.e.
for (i in 1:2) {
write.table( mat[rowcropping[2*i-1]:rowcropping[2*i],],paste0("file",i,".dat")
}
Please use reply to all to keep the discussion on the list.
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Sent from my phone. Please excuse my brevity.
Hans Thompson <hans.thompson1 at gmail.com> wrote:
I am working with matrices that represent images. I believe its important to create them as new objects because what I would like to export these cropped images as new files. Sorry if I didn't include that if it as important information. On Sun, Nov 11, 2012 at 1:36 PM, Jeff Newmiller <jdnewmil at dcn.davis.ca.us>wrote:
I assiduously avoid automatically generating distinct objects, and recommend that you also do so. You have the data, and can refer to individual rows by index as you
need
them.
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Jeff Newmiller The ..... ..... Go
Live...
DCN:<jdnewmil at dcn.davis.ca.us> Basics: ##.#. ##.#. Live
Go...
Live: OO#.. Dead: OO#..
Playing
Research Engineer (Solar/Batteries O.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#.
rocks...1k
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Sent from my phone. Please excuse my brevity. Hans Thompson <hans.thompson1 at gmail.com> wrote:
Hello r-help, I've been banging my head against the computer in an attempt to
learn
how to divide my matrix into segments by rows. I want to be able to
return
each segment as a newly named object. I've tried looking at the apply functions and creating a for loop but brain no work. Here's the basic
starting
objects that I believe would be needed to separate the matrix.
mat <- matrix(c(1:40),10,4)
rowcropping <- sort(sample(2:9,2))
rowcropping <- c(1,rowcropping,length(mat[,1]))
mat[rowcropping[1]:rowcropping[2],]
I want something like the last line as the first object but getting
them
all by automation as separate objects is my goal. Thanks.
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