Hi
It is recommended to keep your emails in Rhelp, there are others who could give you answer.
If I understand correctly you want to take 2 lines in your data frame and test them if they are same but just reversed.
One option could be to split the whole data frame in chunks. Based on your example
test <- structure(list(V1 = c("G1", "G2", "G3", "G1", "G20", "G21"),
V2 = c("G2", "G1", "G1", "G3", "G21", "G16")), class = "data.frame", row.names = c(NA, -6L))
test.l <- split(test, rep(1:3, each=2))
res <- rep(NA, length(test.l))
for (i in 1:length(test.l)) res[i] <- prod(as.numeric(factor(unlist(test.l[[i]]))))
test$column3 <- rep(res==4, each=2)*1
Maybe some clever matrix operations could do it in more elegant way.
Cheers
Petr
S pozdravem | Best Regards
RNDr. Petr PIKAL
Vedouc? V?zkumu a v?voje | Research Manager
PRECHEZA a.s.
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From: Hesham A. AL-bukhaiti <heshamibb at yahoo.com>
Sent: Tuesday, September 15, 2020 1:48 PM
To: PIKAL Petr <petr.pikal at precheza.cz>
Subject: Re: [R] Loop for two columns and 154 rows
thanks petr v much
i attached my problem in word and my data
i want take all elements them have relations not just G1 and G2 this just example test (G1 AND G2) i want make loop to take all elements:
G1 G2 1
G2 G1 1
G3 G1 1
G1 G3 1
G20 G21 0
G21 G16 0
(notice (G1 and G2 have relation and G3 and G1 also have but G20 ,G21,G16 do not have this relations we put 0 ,
(i have G1 to G154) them make 23400 relation i want to know wich forn theses relations are true (1) or not (0)
i hope you can help me.
On Tuesday, September 15, 2020, 02:54:27 AM PDT, PIKAL Petr <petr.pikal at precheza.cz <mailto:petr.pikal at precheza.cz> > wrote:
Sorry, forgot to copy to r help. Petr
-----Original Message----- From: PIKAL Petr Sent: Tuesday, September 15, 2020 11:53 AM To: 'Hesham A. AL-bukhaiti' <heshamibb at yahoo.com <mailto:heshamibb at yahoo.com> > Subject: RE: [R] Loop for two columns and 154 rows Hi Your mail is unreadable, post in plain text not HTML. If I deciphered it correcttly you want all values which have G1 in column 1 and G2 in column 2 or G2 in column 1 and G1 in column to produce 1 all other produce 0 So if your data frame is named truth truth$column3 <- ((truth[,1] =="G1" & truth[,2] =="G2") | (truth[,2] =="G1" & truth[,1] =="G2")) * 1 Cheers Petr
-----Original Message-----
From: R-help <r-help-bounces at r-project.org <mailto:r-help-bounces at r-project.org> > On Behalf Of Hesham A. AL-
bukhaiti via R-help
Sent: Tuesday, September 15, 2020 11:01 AM
To: r-help at r-project.org <mailto:r-help at r-project.org>
Subject: [R] Loop for two columns and 154 rows
Dears in R :i have this code in R:
# this for do not work true (i tried )out<-read.csv("outbr.csv") truth<-
out[,seq(1,2)]truth<-
cbind(as.character(truth[,1]),as.character(truth[,2])
,as.data.frame(rep(
0,,dim(out)[1])));for (j in 1:2) { for (i in 1:20) { truth[(truth[,1]== truth[j,i] &
truth[,2]== truth[j,i+1]) | (truth[,1]== truth[j+1,i] & truth[,2]==
truth[j+1,i+1]),3]<-1 } }
#truth<-out[,seq(1,2)]#truth<-
cbind(as.character(truth[,1]),as.character(truth[,2]) #
,as.data.frame(rep
(0,,dim(out)[1])));#truth[(truth[,1]=="G2" & truth[,2]=="G1") |
(truth[,1]=="G1"
& truth[,2]=="G2"),3]<-1
#################################################################
#########3 I have file have two columns . data in this file is text just (G1,G2,G3? to G154). one element can repeat, no problem ,so we have 23562 rows in two columns (for 154 elements) like : Column1 column2 column3 G1 G4 0 G4 G6 0 G100 G7 1G7 G100 . 1. .. .
I
want to make third column (1 or 0) based on this condition:
IF truth[,1]==?G1? & truth[,2]==?G2? | truth[,1]==?G2? & truth[,2]==?G1? <-
1.then In the third column write 1 otherwise write 0.G1 and G2 just
exampl (indeed i want test If two each elements has a reciprocal
relationship(G1 to G2 and G2 to G1or not) Best regHesham
[[alternative HTML version deleted]]
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