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Applying function to a TABLE and also "apply, tapply, sapply etc"
5 messages · Amelia Vettori, Liviu Andronic, Seeliger.Curt at epamail.epa.gov +1 more
On Wed, Dec 15, 2010 at 4:18 PM, Amelia Vettori
<amelia_vettori at yahoo.co.nz> wrote:
Dear R-help forum members,
Suppose I have a data-frame having two variables and single data for each of them, as described below.
variable_1?????????? variable_2
??????? 10????????????????????????? 20
I have written a function, say, 'fun' which uses input 10 and 20 and gives me desired result.
fun = function(X, Y)
???????? {
???????? X + Y????????????? #( I am just giving an example of process. Actual process is
?quite different.)
???????? }
result = fun(variable_1[1], variable_2[1])?? # Thus, i should be getting answer 30 which I am storing in say 'ans1.csv'
# ____________________________________________________________________
# My problem
Suppose instead of having above dataframe having single data for variable 1 and variable 2, I have following data as
variable_1?????????? variable_2
?????? 10???????????????????????? 20
??????? 40 ? ????????????????????? 30
??????? 3????????????????????????? 11
I need to run the function 'fun' for each pair of values taken by variable_1 and variable_2 separately. Also, the results (= 30, 70 and 14) obtained for each of above pairs should be stored in different csv files, say "ans1.csv", "ans2.csv" and "ans3.csv" respectively which I can use for further analysis. (In reality each of these output files will consists of 1000 records).
As I had mentioned in my earlier mail, I am new to R and I think I
?should be using apply or sapply or tapply etc., which I have tried but I am not able to proceed further as I am not able to understand it properly.
It will be a great help to me if I receive the guidance w.r.t
(a) how do I tackle above problem i.e. how do I apply the function to a table so that it will generate different csv files pertaining to pair of values "10 and 20", "40 and 30" and "3 and 11";
Say you have the following data frame
df
Var1 V2 1 10 20 2 40 30 3 3 11
str(df)
'data.frame': 3 obs. of 2 variables: $ Var1: num 10 40 3 $ V2 : num 20 30 11 Then
apply(df, 1, sum) ##compute sum() for each row
1 2 3 30 70 14
apply(df, 2, sum) ##compute sum() for each column
Var1 V2 53 61
(b) I am not that sharp to understand the programming aspects of R taht easily, though I am really keen to learn R, so I will be highly obliged if someone helps me understand with some simple examples as to how "apply", "supply", "tapply", "mapply" etc can be used?
Only some examples that I understand well. ##apply function to each element of a list (data frames are lists) ##compute sum() for each column
lapply(df, sum)
$Var1 [1] 53 $V2 [1] 61 ##sapply() is a variation of lapply(); see the docs
sapply(df, sum)
Var1 V2 53 61 ##using the 'iris' data frame, for each Species level compute mean() of the Sepal.Length column
with(iris, tapply(Sepal.Length, Species, mean))
setosa versicolor virginica
5.006 5.936 6.588
##a friendlier interface is provided by by()
with(iris, by(Sepal.Length, Species, mean))
Species: setosa [1] 5.006 ------------------------------------------------------------ Species: versicolor [1] 5.936 ------------------------------------------------------------ Species: virginica [1] 6.588 ##the same, now for four variables at the same time
by(iris[1:4], iris$Species, mean)
iris$Species: setosa
Sepal.Length Sepal.Width Petal.Length Petal.Width
5.006 3.428 1.462 0.246
------------------------------------------------------------
iris$Species: versicolor
Sepal.Length Sepal.Width Petal.Length Petal.Width
5.936 2.770 4.260 1.326
------------------------------------------------------------
iris$Species: virginica
Sepal.Length Sepal.Width Petal.Length Petal.Width
6.588 2.974 5.552 2.026
For an example of mapply see this recent post:
http://r.789695.n4.nabble.com/calculating-mean-of-list-components-tp3088986p3089057.html
For more on vectorization, see sections 3 and 4 of the 'R inferno'
[1]. Also check 'Some Hints for the R Beginner' [2].
[1] http://www.burns-stat.com/pages/Tutor/R_inferno.pdf
[2] http://www.burns-stat.com/pages/Tutor/hints_R_begin.html
Regards
Liviu
I am sure this will go a long way in helping the new learners like me to undesrtand the proper use of these wonderful commands. I hope I am able to put forward my problem properly. Thanking all in advance for the anticipated guidance Amelia ?Vettori, Auckland ? ? ? ?[[alternative HTML version deleted]]
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On 12/15/2010 7:18 AM, Amelia Vettori wrote:
Dear R-help forum members,
Suppose I have a data-frame having two variables and single data for
each of them, as described below.
variable_1 variable_2 10 20
I have written a function, say, 'fun' which uses input 10 and 20 and
gives me desired result.
fun = function(X, Y) { X + Y #( I am just giving an
example of process. Actual process is quite different.) }
result = fun(variable_1[1], variable_2[1]) # Thus, i should be
getting answer 30 which I am storing in say 'ans1.csv'
#
____________________________________________________________________ # My problem Suppose instead of having above dataframe having single data for variable 1 and variable 2, I have following data as variable_1 variable_2 10 20 40 30 3 11 I need to run the function 'fun' for each pair of values taken by variable_1 and variable_2 separately. Also, the results (= 30, 70 and 14) obtained for each of above pairs should be stored in different csv files, say "ans1.csv", "ans2.csv" and "ans3.csv" respectively which I can use for further analysis. (In reality each of these output files will consists of 1000 records). As I had mentioned in my earlier mail, I am new to R and I think I should be using apply or sapply or tapply etc., which I have tried but I am not able to proceed further as I am not able to understand it properly. It will be a great help to me if I receive the guidance w.r.t (a) how do I tackle above problem i.e. how do I apply the function to a table so that it will generate different csv files pertaining to pair of values "10 and 20", "40 and 30" and "3 and 11"; (b) I am not that sharp to understand the programming aspects of R taht easily, though I am really keen to learn R, so I will be highly obliged if someone helps me understand with some simple examples as to how "apply", "supply", "tapply", "mapply" etc can be used? I am sure this will go a long way in helping the new learners like me to undesrtand the proper use of these wonderful commands. I hope I am able to put forward my problem properly. Thanking all in advance for the anticipated guidance Amelia Vettori, Auckland
# a slightly more complicated demonstration function, which
# gives a result that make sense for writing to a CSV file.
fun <- function(X, Y) {
data.frame(result=X + Y)
}
foo <- data.frame(variable_1=c(10,40,3), variable_2=c(20,30,11))
# using apply
# This only really works if the columns in foo are the same
# type because it will be transformed into a matrix (which
# is of one type). Also, since the column names of the data.frame
# don't match the arugments of fun, the unname is needed.
# do.call is a somewhat advanced function that lets you call
# a function with arguments that are stored in some other
# list.
apply(foo, 1, function(x) do.call("fun", as.list(unname(x))))
# version using apply, where foo has been transformed into
# something more like what apply would expect.
foo.m <- as.matrix(foo)
colnames(foo.m) <- c("X","Y")
apply(foo.m, 1, function(x){do.call("fun", as.list(x))})
# using lapply
# lapply takes a list, which for this looping purpose would have
# to be the row indexes of foo. This version does not reqire
# the different arguements to be the same type.
lapply(1:nrow(foo), function(i) {fun(foo[i,1],foo[i,2])})
# using mapply
# This one is more designed for when multiple arguments to a
# function are changing.
mapply(fun, foo[,1], foo[,2])
# using Vectorize
# A different approach, where instead of creating the looping
# structure, create a new function which is vectorized over its
# arguements.
fun.v <- Vectorize(fun)
fun.v(foo[,1], foo[,2])
# storing the results to disk
results <- mapply(fun, foo[,1], foo[,2])
# results is a list, each element of which is one of the returned
# sets of results corresponding to a row in the original data.frame
lapply(1:length(results), function(r) {write.csv(results[r],
file=paste("ans",r,".csv",sep=""))})
# if you didn't need different file names (the name of which depends on
# the position of the result in the list, not anything in the result
# itself), it could be simpler.
lapply(results, summary)
Brian S. Diggs, PhD Senior Research Associate, Department of Surgery Oregon Health & Science University