I know that maybe it will be stupid question.
What iswrong with it (i think that i have to do the "stop moment", but i
dont know how)
fibbonacci=function(x) {
while(x>0) {
if (x==1 || x==2) {
return(1)
} else fibbonacci(x-1)+fibbonacci(x-2)
}
}
--
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Problem with recursion
3 messages · R. Michael Weylandt, Haszun
On Sat, Nov 10, 2012 at 7:41 AM, Haszun <crazystef13 at tlen.pl> wrote:
I know that maybe it will be stupid question.
What iswrong with it (i think that i have to do the "stop moment", but i
dont know how)
fibbonacci=function(x) {
while(x>0) {
if (x==1 || x==2) {
return(1)
} else fibbonacci(x-1)+fibbonacci(x-2)
}
}
Just a hint: do you need a while condition? If so, might a return() help you out? If not, what's the cleanest way to eliminate it? Note that R has the convention that the final value in the function is the one returned, but that constructs like this can trip you up: x <- 5 while(x > 0) x <- x - 1 print(.Last.value) Cheers, Michael
Thank you for help. -- View this message in context: http://r.789695.n4.nabble.com/Problem-with-recursion-tp4649162p4649166.html Sent from the R help mailing list archive at Nabble.com.