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Changing x-axis when dealing with time
3 messages · Pablo Rosado, Kenneth Takagi
2 days later
Pablo Rosado <pablojrosado <at> lbl.gov> writes:
Hi,
I am plotting data in which the x values are a timestamp. I am trying to
change the x-ticks so they will be in specified hours of the day, but it
always start from hour 4 of the day. And I need it to start from the
beginning of the axis (at x=0) and then each tick be on the interval I
specify.
Here is my plotting script:
*##-- ROOF COMPARISON - SOUTH--
win.graph()
plot(x=tiempo,y=timeframe[,8],xlab="",ylab="",**xaxt='n',**
yaxt='n',type="l",col="blue",lwd=3,ylim=c(0,80),font=2,las=1)
axis(side=1,at=seq(0,24,3))
axis(side=2,at=seq(0,80,10),line=NA, tcl = -0.5,font=2,las=1)
lines(x=tiempo,y=timeframe[,47],col="red",lwd=3)
title(xlab=paste("Local Standard Time (",date), cex.lab=1,font.lab=2)
title(ylab="Temperature (?C)", cex.lab=1,font.lab=2)
legend("topleft",legend=c("cool", "standard"),col=c("blue",
"red"),lwd=c(4,4),bty="n",cex=1.25)
grid(nx=NULL,ny=NULL,col = "gray", lty = "dotted",lwd = 1)*
But with the axis(side=1...) nothing appears.
I have been practicing with the following code to change the xaxis but it
says that x and y lengths differ:
*## TIMESTAMP IS A ONE COLUMN VECTOR IN WHICH I SAVED THE TIMESTAMP FROM MY
FILE
string.to.time <-
function(timestamp)
strptime(x=timestamp, format="%Y-%m-%d %H:%M:%S")
decimal.day <-
function(timestamp) {
y <- as.POSIXlt(**timestamp**)
y$day + y$hour/24 + y$min/(24*60) + y$sec/(24*60*60)
}
decimal.hour <-
function(**timestamp**) {
dd <- decimal.day(**timestamp**)
24 * (dd - floor(dd))
}
##create some data to plot
t.start <- string.to.time("2011-05-02 00:00:00")
t.start
t.vector <- t.start + (0:24)*3600
t.vector
z.vector <- 1:length(t.vector)
z.vector
##vector of decimal hours
dh.vector <- decimal.hour(t.vector)
dh.vector
plot(x=dh.vector, y=z.vector, xlim=c(0,24), xaxt="n", xlab="Hour of day",
ylab="Some property")
*
Thank You so much and have a great weekend.
Hi Pablo,
I'm a big fan of the "chron" package for plotting dates on axis. Not sure if
this is what you are looking for,but might be helpful. Here is a simple example
using the chron package and plotting dates on x-axis. You can alter the text
labels on x-axis using substr() on the date vector.
# create "chron" time vector
library(chron)
excel.dates <- seq(40179.0 + 1/6, 40180.0 + 1/6, 1/6)
orig <- chron("12/30/1899")
date.time <- orig + excel.dates;
time.only <- substr(date, 11, 18)
# Y data
y.dat = rnorm(7, 10, 3)
# Plot it up! Don't add annotations or axes for now
plot(date.time, y.dat, type="n", ann=F, axes=F)
# Add data
lines(date.time, y.dat, lwd = 2, col = "black")
points(date.time, y.dat, pch = 20, col = "magenta")
box() # add box around plot
# Add X-Axis and label
axis(1, at=c(seq(date.time[1], date.time[length(date.time)],1/6)), tck = +0.01,
labels = F)
#label=date.time # prints date and time
label = time.only # only prints time
x.len=length(label)
text(x=date.time[1:x.len], par("usr")[3]-.135, srt = 45, adj = 1,
labels = label, xpd = T)
mtext(side = 1, "Time", line = 3.2) #X-axis label
HTH,
Ken
Ken <katakagi <at> bu.edu> writes:
# create "chron" time vector
library(chron)
excel.dates <- seq(40179.0 + 1/6, 40180.0 + 1/6, 1/6)
orig <- chron("12/30/1899")
date.time <- orig + excel.dates;
time.only <- substr(date, 11, 18)
Found one error in my script above. Correction: time.only <- substr(date.time, 11, 18) Ken