Mahbub's solution
data.frame(t(sapply(...)))
is much faster than
do.call("rbind", lapply(...))
as tested on a larger dataset.
Thanks everyone,
Remko Duursma
--
On Tue, 15 Apr 2003 22:10:28
Mahbub Latif wrote:
you can try this,... data.frame(t(sapply(tester.L, function(x) x <- x[1,] ))) Mahbub. --- Remko Duursma <den.duurs at lycos.com> wrote:
Dear R-helpers,
i have a question on how to vectorize this problem:
i have a dataframe:
tester <-
data.frame(groups=c("A","A","B","B","C","C"),
one=c(1,1,2,2,3,3), two=c(6,6,7,7,8,8))
# i split it into a list
tester.L <- split(tester, tester$groups)
# And want to keep only the first item in each:
lapply(tester.L, function(x) x <- x[1,] )
How do i make a dataframe out of the last result,
which looks like "tester", without looping? (i can
use rbind in a for loop, but is rather slow)
thanks for your help,
Remko Duursma
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