Long story short, I have a big iterative procedure that produces a long list of data.frames such as the one called
"results" here. ?Is there an easy way to produce a similar list of data.frames comprised of the mean of each of the
columns in results, such that it ends up like the one I've shown in "resultsmean" below?
I've tried apply and lapply, still not got the correct arguments. ?As usual, TIA.
Jim
[[1]]
? ? ? name ? ?LOR23 ? ? ? BIA23 ? ? ? MSE23 ? ? ? ? ?H0R23
1 0.2111122 ? -1.012228 ? -0.095937 ? ?0.035650 ? ? ? ?1.00
2 0.2111122 ? -0.836300 ? ?0.079991 ? ?0.042322 ? ? ? ?0.75
3 0.2111122 ? -0.518631 ? ?0.397659 ? ?0.214593 ? ? ? ?0.50
[[2]]
? ? ? name ? ?LOR23 ? ? ? BIA23 ? ? ? MSE23 ? ? ? ? ?H0R23
1 0.2211122 ? -0.724630 ? ?0.191660 ? ?0.051308 ? ? ? ? ? 1
2 0.2211122 ? -0.781812 ? ?0.134478 ? ?0.033872 ? ? ? ? ? 1
3 0.2211122 ? -0.522109 ? ?0.394181 ? ?0.164628 ? ? ? ?0.75
would like
[[1]]
? ? ? name ? ?LOR23 ? ? ? BIA23 ? ? ? MSE23 ? ? ? ? ?H0R23
1 0.2111122 ? -0.78333 ? ?0.12734 ? ? 0.097160 ? ? ? ?0.75
[[2]]
? ? ? name ? ?LOR23 ? ? ? BIA23 ? ? ? MSE23 ? ? ? ? ?H0R23
1 0.2211122 ? -0.67566 ? ?0.2400 ? ? ?0.08266 ? ? ? ? 0.916
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Dr. Jim Maas
University of East Anglia