Hello!
I have my data frame x with 2 character columns:
x <- data.frame(a = numeric(), b = I(list()))
x[1:3,"a"] = 1:3
x[[1, "b"]] <- "a, b, c"
x[[2, "b"]] <- "d, e"
x[[3, "b"]] <- "f"
x$a = as.character(x$a)
x$b = as.character(x$b)
x
str(x)
I need to produce this data frame:
1 a
1 b
1 c
2 d
2 e
3 f
Is it possible without looping?
Thank you!
first second
1 1 a
2 1 b
3 1 c
4 2 d
5 2 e
6 3 f
Maybe you want to remove extra white space form your values. It is mentioned somewhere in help pages to regular expressions
Cheers
Petr
-----Original Message-----
From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Dimitri
Liakhovitski
Sent: Thursday, April 23, 2015 3:15 PM
To: r-help
Subject: [R] reshape data frame when one column has unequal number of
entries
Hello!
I have my data frame x with 2 character columns:
x <- data.frame(a = numeric(), b = I(list()))
x[1:3,"a"] = 1:3
x[[1, "b"]] <- "a, b, c"
x[[2, "b"]] <- "d, e"
x[[3, "b"]] <- "f"
x$a = as.character(x$a)
x$b = as.character(x$b)
x
str(x)
I need to produce this data frame:
1 a
1 b
1 c
2 d
2 e
3 f
Is it possible without looping?
Thank you!
--
Dimitri Liakhovitski
________________________________
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Hi Dimitri
here is a quick crude way (needs some polishing)
data.frame(a = rep(x$a,sapply(sapply(x$b, strsplit, ", "), length)), b=
unlist(sapply(x$b, strsplit, ", ")))
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home: mackay at northnet.com.au
-----Original Message-----
From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Dimitri
Liakhovitski
Sent: Thursday, 23 April 2015 23:15
To: r-help
Subject: [R] reshape data frame when one column has unequal number of
entries
Hello!
I have my data frame x with 2 character columns:
x <- data.frame(a = numeric(), b = I(list()))
x[1:3,"a"] = 1:3
x[[1, "b"]] <- "a, b, c"
x[[2, "b"]] <- "d, e"
x[[3, "b"]] <- "f"
x$a = as.character(x$a)
x$b = as.character(x$b)
x
str(x)
I need to produce this data frame:
1 a
1 b
1 c
2 d
2 e
3 f
Is it possible without looping?
Thank you!
On Thu, Apr 23, 2015 at 10:38 AM, Duncan Mackay <dulcalma at bigpond.com> wrote:
Hi Dimitri
here is a quick crude way (needs some polishing)
data.frame(a = rep(x$a,sapply(sapply(x$b, strsplit, ", "), length)), b=
unlist(sapply(x$b, strsplit, ", ")))
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
Armidale NSW 2351
Email: home: mackay at northnet.com.au
-----Original Message-----
From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Dimitri
Liakhovitski
Sent: Thursday, 23 April 2015 23:15
To: r-help
Subject: [R] reshape data frame when one column has unequal number of
entries
Hello!
I have my data frame x with 2 character columns:
x <- data.frame(a = numeric(), b = I(list()))
x[1:3,"a"] = 1:3
x[[1, "b"]] <- "a, b, c"
x[[2, "b"]] <- "d, e"
x[[3, "b"]] <- "f"
x$a = as.character(x$a)
x$b = as.character(x$b)
x
str(x)
I need to produce this data frame:
1 a
1 b
1 c
2 d
2 e
3 f
Is it possible without looping?
Thank you!
--
Dimitri Liakhovitski