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order() and na.last

2 messages · Richards, Tom, Uwe Ligges

#
Hello:

	I'm not sure what is going on in these two statements.  the first
seems to be right, but the second is a problem:
[1] 2 1 3 4
Error in .NotYetUsed("na.last != TRUE") : argument `na.last != TRUE' is not
used (yet)
I am using R 1.2.2 under Windows NT.  Thanks.


Tom
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#
"Richards, Tom" wrote:
Let's read the help (?order): 

na.last:  for controlling the treatment of `NA's. If `TRUE', missing
          values in the data are put last; if `FALSE', they are put
          first; if `NA', they are removed. Currently, `TRUE' is the
          only possible value.

To point it out: "Currently, 'TRUE' is the only possible value.

Uwe Ligges
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