better than sapply

I have the following two mapping data frames (r) and (h). I want to
fill teh value of r$seid with the value of r$seid where r$cid==h$cid.
I can do it with sapply as such:

r$seid = sapply(r$cid, function(cid) h[h$cid==cid,]$seid)

Is ther a better (faster) way to do this?

r <- data.frame(seid=NA, cid= c(2181,2221,2222))
r

 seid      cid
1  NA    2181
2  NA    2221
3  NA    2222

h <- data.frame(seid= c(5598,5609,4931,5611,8123,8122), cid= c(2219,2222,2181,2190,2817,2221))
h

    cid  seid
1 5598 2219
2 5609 2222
3 4931 2181
4 5611 2190
5 8123 2817
6 8122 2221

to get the desired result of:

r

 seid  cid
1 4931 2181
2 8122 2221
3 5609 2222