Message-ID: <C9D68928-9137-489F-BA69-7973F4FF7237@oulu.fi>
Date: 2019-05-09T08:00:03Z
From: Jari Oksanen
Subject: transformation of Bray-Curtis in Euclidean
In-Reply-To: <CAKJjPx7XTW_WEP51kc8YDDQ0cvXC8DfkOVVCzpvus6rRyKu=1A@mail.gmail.com>
Yes, it is possible, and always has been when I have checked (which is not a proof). You can check this by seeing that it has no negative eigenvalues in principal coordinates analysis (apart from occasional negative almost-zero). Legendre & Legendre book discuss this.
Cheers, Jari Oksanen
> On 9 May 2019, at 10:21, Irene Adamo <i.adamo90 at gmail.com> wrote:
>
> Hi all,
>
> I have a very simple question: is it possible that the square-root of
> Bray-Curtis values is Euclidean? if not, is there a way to transform
> bray-curtis which is semi-quantitative in Euclidean?
>
> thanks a lot!
>
> [[alternative HTML version deleted]]
>
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