Crosses above, crosses below
On Wed, Oct 2, 2013 at 9:02 AM, Joshua Ulrich <josh.m.ulrich at gmail.com> wrote:
<SNIP>
Your original question only asked about a cross above. If you want to test for a cross below, you need to test EMA.10 < EMA.20. If you want both crosses in one column, you can combine them by checking when the diffs of the logical comparisons equal 1. (diff(EMA.10 > EMA.20)==1) - (diff(EMA.10 < EMA.20)==1) Now the cross above will be 1 and the cross below will be -1.
Again, thanks for the example code. It's helpful. Cheers, Mark
Fair enough. I think this still misses the issue I was concerned about but I wrote some functions that work the way I want using your inputs so I'm set for now. Thanks! Cheers, Mark