insert element in IBrokers/XTS time series?
If you are simply looking to make an irregular series 'regular' per some time-scale (e.g. days), you can merge with a zero-width xts object or a time-based vector: ?merge.xts and example(merge.xts) will give you some tips.
reg.time <- timeBasedSeq('20090625/20090703') # creates a 'Date' vector, use retclass to override if needed
reg.time
[1] "2009-06-25" "2009-06-26" "2009-06-27" "2009-06-28" "2009-06-29" [6] "2009-06-30" "2009-07-01" "2009-07-02" "2009-07-03" # get some daily data
getSymbols("AAPL", from='2009-06-25')
AAPL
AAPL.Open AAPL.High AAPL.Low AAPL.Close AAPL.Volume AAPL.Adjusted 2009-06-25 135.75 140.20 135.21 139.86 21051700 139.86 2009-06-26 139.79 143.56 139.74 142.44 15692300 142.44 2009-06-29 143.46 143.95 141.54 141.97 20272000 141.97 2009-06-30 142.58 143.80 141.80 142.43 15508000 142.43 2009-07-01 143.50 144.66 142.52 142.83 14792100 142.83 2009-07-02 141.25 142.83 139.79 140.02 13231400 140.02
merge(AAPL,reg.time)
AAPL.Open AAPL.High AAPL.Low AAPL.Close AAPL.Volume AAPL.Adjusted 2009-06-25 135.75 140.20 135.21 139.86 21051700 139.86 2009-06-26 139.79 143.56 139.74 142.44 15692300 142.44 2009-06-27 NA NA NA NA NA NA 2009-06-28 NA NA NA NA NA NA 2009-06-29 143.46 143.95 141.54 141.97 20272000 141.97 2009-06-30 142.58 143.80 141.80 142.43 15508000 142.43 2009-07-01 143.50 144.66 142.52 142.83 14792100 142.83 2009-07-02 141.25 142.83 139.79 140.02 13231400 140.02 2009-07-03 NA NA NA NA NA NA HTH, Jeff
On Fri, Jul 3, 2009 at 7:01 PM, Michael<comtech.usa at gmail.com> wrote:
Hi all, Let's say I have the following timeseres in IBrokers and XTS: 2009-06-25 ? ? ?18038 ? ? ?18350 ? ? 18011 ? ? ? 18327 ? ? ? ? 5396 ? ? 18183 2009-06-26 ? ? ?18420 ? ? ?18708 ? ? 18331 ? ? ? 18515 ? ? ? ? 7367 ? ? 18499 2009-06-29 ? ? ?18546 ? ? ?18688 ? ? 18423 ? ? ? 18577 ? ? ? ?28728 ? ? 18555 2009-07-03 ? ? ?17951 ? ? ?18198 ? ? 17866 ? ? ? 18149 ? ? ? ?38019 ? ? 18059 I want to add a few more rows, indexed by "2009-06-30", "2009-07-01", "2009-07-02", and using NA's, I did the following: myhist["2009-07-01",]=c(NA, NA, NA, NA, NA, NA, NA, NA) But it didn't really work. What's the good way to insert missing points in time series? Thanks!
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Jeffrey Ryan jeffrey.ryan at insightalgo.com ia: insight algorithmics www.insightalgo.com