spatially clustered factors?
Great thanks it worked a treat; a lot of time in R being pointed to the correct package / function is all that is needed. Chris -----Original Message----- From: Roger Bivand [mailto:Roger.Bivand at nhh.no] Sent: 01 July 2013 12:12 To: Chris Mcowen Cc: r-sig-geo at r-project.org Subject: Re: [R-sig-Geo] spatially clustered factors?
On Mon, 1 Jul 2013, Chris Mcowen wrote:
Dear list, first let me apologise, i am an ecologist and this is my first foray into spatial statistics. I have, for a number of regions, the factor that best explains variation in the yield (fisheries catch) obtained within that region, the factor has 4 levels - ChlA, SST, Effort or none.
See joincount.test for single comparisons, or joincount.multi for multiple
comparisons by join "colours" in spdep. You'll also need neighbour lists,
explained in:
vignette("nb")
in the most recent version of that package.
Hope this helps,
Roger
What i am essentially wanting to know is, is there a spatial pattern
to the data? (clumped, over-dispersed or random)
For example if region 1 is classed as Effort, is it more or less
likely that the adjoining region (region 2) will be of the same
factor, or does it makes no difference.
I have seen lots of packages that allow this to be done for numerical
data but have not found one for factors.
Please see below for an example of the data. Where latitude is the
centroid of the region and factor is the source of variation.
clusters <- structure(list(Latitude = c(4.8261, 26.127123, 3.409063,
-31.964573, 11.524328, 10.857926, 30.95066, 6.322733, 40.963009,
-4.370738, 53.77057, -46.270909, 51.431808, 50.091992, -12.606217,
16.26404, -27.513126, -40.976427, -40.491914, -35.169487, -16.739053,
-22.651113, 30.445027, -27.701939, -17.154608, -10.147356, -29.117245,
57.472215, 45.538569, 65.31731, 75.308501, 54.063299, 45.194528,
41.079154, -35.169487, 51.431808, 24.647845, 68.201714, 41.262656,
24.976371, 33.251908, 16.347456, 30.95066, -1.408364, 37.054319,
23.843305, 57.400753, 8.712258), Factor = structure(c(1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L,
4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L, 4L), .Label = c("ChlA", "Effort",
"SST", "Unidentified"), class = "factor")), .Names = c("Latitude",
"Factor"), class = "data.frame", row.names = c(NA, -48L))
Thanks,
Chris
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-- Roger Bivand Department of Economics, NHH Norwegian School of Economics, Helleveien 30, N-5045 Bergen, Norway. voice: +47 55 95 93 55; fax +47 55 95 95 43 e-mail: Roger.Bivand at nhh.no