[FORGED] Modifying the length of a matrix variable
Yes, I reproduced the example above and it works just fine (and is what I want!!), but I cannot see why it does not work with my data, as it is a 3-dimensional array (latitude, longitude and time).?
This is what comes from print(Model4):
3 variables (excluding dimension variables):
double onedaymax[lon,lat,time] (Contiguous storage)
units: mm/day
double fivedaymax[lon,lat,time] (Contiguous storage)
units: mm/day
short Year[time] (Contiguous storage)
3 dimensions:
time Size:95
lat Size:64
units: degree North
lon Size:128
units: degree East
I reviewed it over and over again, but I cannot see why this would not work?
Thanks,?
-----Original Message-----
From: Rolf Turner <r.turner at auckland.ac.nz>
To: rain1290 <rain1290 at aim.com>
Cc: r-sig-geo <r-sig-geo at r-project.org>
Sent: Sat, Mar 30, 2019 6:49 pm
Subject: Re: [FORGED] [R-sig-Geo] Modifying the length of a matrix variable
On 31/03/19 11:14 AM, rain1290 at aim.com wrote:
Hi Rolf (and others), I tried your suggestion, but when I used dim(Model4.chopped), it still shows 95 layers, as shown below: 8192 ?? 95 I also find that the total number of cells is rather low for that many layers. I started with 778240 cells over 95 layers.
Well then you're doing something wrong, or there is something that you haven't told us. E.g.:
junk <- array(runif(64*128*95),dim=c(64,128,95)) junk.chopped <- junk[,,1:90] dim(junk) [1]? 64 128? 95 dim(junk.chopped) [1]? 64 128? 90
Perhaps Model.4 has some structure other than that of an array. (Originally you said it was a matrix.) You really need to get your terminology and ideas *clear* in order to have any hope of receiving useful advice. I have no idea what you are on about in respect of "the number of cells".? My mind-reading machine is in the repair shop.? I strongly suspect that your thoughts are confused. cheers, Rolf
Honorary Research Fellow Department of Statistics University of Auckland Phone: +64-9-373-7599 ext. 88276 [[alternative HTML version deleted]]