Time vs. Longitude (Hovmueller Diagram)

At a guess, for a given latitude you could do this where "x" is a
data.frame with columns Longitude, Latitude, Time1, ..., TimeN

x1 <- x["Latitude" == -29, ]

## very simplistically

## drop Latitude, and order by Longitude (assuming Time columns are in
the right order)
x2 <- as.matrix(x1[order(x1$Longitude),  -2]

image(x2)

## with a bit more work, but big assumptions

lon <- sort(x1$Longitude)
tm <- as.numeric(colnames(x2)[-1])

image(lon, tm, x2, main = "Latitude -29", xlab = "Longitude", ylab = "Time")


There's a lot of guessing here for us, can you describe the file more
exactly or provide a link to at least one latitude's worth?

The Spatial classes in sp provide much more structured support for
these grids, and the spacetime package even more for generalizing
further - but they rely on exactly regular grids, which it looks like
you have here.

Cheers, Mike.

Dear Experts,

I am trying to plot the Hovmueller Diagram (example below), which is time
vs. longitude in R.

http://www.esrl.noaa.gov/psd/cgi-bin/hovmoller/timeplot.pl?var=air&level=1000&mon1=1&mon2=1&dy1=1&dy2=31&yr1=2010&yr2=2011&datatype=operational&type=mean&fxdlon=no&postscript=no&lon1=&lon2=&lat1=&lat2=&cint=&lowr=&highr=&size=100&Submit=Create+Plot

But I couldn't make it work at the moment. Could anyone please suggest me
which package or function in R can plot such a graph?

The data file on hand is like:

Longtitude ? Latitude ? Time1.....................TimeN
? 124 ? ? ? ? ? ?-29
? 126 ? ? ? ? ? ?-29 ? ? ? ? ?.......................................
? 128 ? ? ? ? ? ?-29
? ? .. ? ? ? ? ? ? . .

2520 spatial locations corresponding to an 84 (longitude) by 30 (latitude)
grid with 2 degree x 2 degree spacing.

Thank and Regards

Fred

? ? ? ?[[alternative HTML version deleted]]

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Michael Sumner
Institute for Marine and Antarctic Studies, University of Tasmania
Hobart, Australia
e-mail: mdsumner at gmail.com