Dear, I have a problem with ?spreml? function in R. I have a dataset of 26000 observation, like points. I have imported the shp file in R, and .gal file calculated previously in GEODA. When i run spreml, an error comes: Error in as.vector(x) : no method for coercing this S4 class to a vector below the function: mapsart <- spreml(fm, data = map, w = maplistw, errors="sr", lag=TRUE, method="BFGS?) Can you help me to solve this problem? Regards Federico
spreml function
2 messages · Federico Dell'Anna, Roger Bivand
6 days later
On Thu, 11 Apr 2019, Federico Dell'Anna wrote:
Dear, I have a problem with ?spreml? function in R. I have a dataset of 26000 observation, like points. I have imported the shp file in R, and .gal file calculated previously in GEODA. When i run spreml, an error comes: Error in as.vector(x) : no method for coercing this S4 class to a vector below the function: mapsart <- spreml(fm, data = map, w = maplistw, errors="sr", lag=TRUE, method="BFGS?)
Unfortunately, this is not helpful, as we do not know what the objects passed to spreml() are. What are their classes? Is data= of the form expected by the function with balanced temporal and spatial indices? Please provide an example reproducing the problem with a built-in data set. Roger
Can you help me to solve this problem? Regards Federico [[alternative HTML version deleted]]
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