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sp.correlogram

2 messages · Kitty Lee, Roger Bivand

#
On Sun, 26 Aug 2007, Kitty Lee wrote:

            
Your k=5 k-nearest neighbours are first order neighbours. You asked for 10 
orders, so you "stepped out": the second order neighbours are the first 
order neighbours of your first order neighbours (omitting observations 
already included), and so on. Have a look (in practice) at what nblag() 
does if this is unclear, and note that for many lattices, there will be 
relatively few or no remaining neighbours at high lags.

Hope this helps,

Roger