Sorting each column of a matrix independently
This question should be directed to R-Help Anyway, sorted <- apply(unsorted,2,sort) should do it. Ken
On 14/10/2010, at 7:06 PM, Desmond Lim wrote:
Hi, I have this matrix unsorted$A with 5 columns (all numeric). Currently I'm sorting the columns like this: sorted$A[,1] <- sort(unsorted$A[,1]) sorted$A[,2] <- sort(unsorted$A[,2]) ... I have tried doing sorted$A <- unsorted$A[do.call(order, data.frame(unsorted$A)),] but it sorts the first column then the 2nd column which it ties to the 1st column, then the 3rd which is tied to the 2nd, etc. I need all the columns to be independently sorted. Any help is appreciated. Desmond
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