Wolfgang Viechtbauer, Ph.D., Statistician | Department of Psychiatry and
Neuropsychology | Maastricht University | P.O. Box 616 (VIJV1) | 6200 MD
Maastricht, The Netherlands | +31 (43) 388-4170 | http://www.wvbauer.com
>-----Original Message-----
>From: R-sig-meta-analysis [mailto:r-sig-meta-analysis-bounces at r-
>project.org] On Behalf Of Naike Wang
>Sent: Friday, July 07, 2017 15:25
>To: r-sig-meta-analysis at r-project.org
>Subject: [R-meta] Freeman-Tukey double arcsine transformation and harmonic
>mean
>
>Hi all,
>I have two questions.
>1) In this article
><https://mail.jjay.cuny.edu/owa/redir.aspx?C=jnnID1xyBS33HM9BECtjC_Z23ilF5
>4mDEf0zdCS88qMPhZkvMsXUCA..&URL=http%3a%2f%2fwww.metafor-
>project.org%2fdoku.php%2fanalyses%3amiller1978>,
>Dr. Wolfgang Viechtbauer used the harmonic mean of the sample sizes to
>back-transform the estimated average transformed proportion (the pooled
>proportion). If I don't want to use the harmonic mean, is it possible to
>use the *transf.ipft*, instead of the *transf**=**transf.ipft.hm
><http://transf.ipft.hm>*, to get the pooled proportion? If so, how do I do
>that?
>
>2) One of the reasons I asked the question is due to this article:
>Meta-analysis
>of prevalence
><https://drive.google.com/open?id=0B41wTxciaMqtNXVSNEFGazdPWFU>. The
>authors of this article developed an Exel-based meta-analysis add-in
>(MetaXL). MetaXL uses a different method to perform the double arcsine
>transformation. The differences are two-fold.
>First, MetaXL uses a different definition of the Freeman-Tukey
>transformation. The PFT values (yi) are twice as large as the values
>computed by metafor and the variances (vi) are four times as large. The
>different definitions are also explained here
><http://www.metafor-project.org/doku.php/faq#how_is_the_freeman-
>tukey_trans>
>.
>Second, it does not use the harmonic mean to perform the
>back-transformation. According to the authors, it is better not to use the
>harmonic mean because their simulation studies suggest that the harmonic
>mean is not stable.
>Basically, I'm asking how to get metafor to get the same results as
>obtained in MetaXL? Do you agree with the MetaXL authors that it is better
>not to use the harmonic mean?
>
>I hope my questions make sense. Feel free to ask me anything if you don't
>understand.
>
>P.S. Dowload MetaXL here: http://www.epigear.com/index_files/metaxl.html
>P.S.S. After you install MetaXL, open example "SchizophreniaPrev" to get a
>sense of how it performs meta-analysis of proportions.
>
>Cheers,
>Naike