-----Original Message-----
From: Tobias Saueressig [mailto:t.saueressig at gmx.de]
Sent: Tuesday, 18 August, 2020 7:40
To: Viechtbauer, Wolfgang (SP)
Subject: Aw: RE: [R-meta] Data Extraction
Dear Wolfgang,
you are my hero. Thank you.
I am a bit sad that I cannot include the study because it is based on change
scores and I have used postintervention only.
Gesendet:?Montag, 17. August 2020 um 22:33 Uhr
Von:?"Viechtbauer, Wolfgang (SP)"
<wolfgang.viechtbauer at maastrichtuniversity.nl>
An:?"Tobias Saueressig" <t.saueressig at gmx.de>, "r-sig-meta-analysis at r-
project.org" <r-sig-meta-analysis at r-project.org>
Betreff:?RE: [R-meta] Data Extraction
Dear Tobias,
The difference between the upper and lower CI bounds divided by the
appropriate critical t-value should be *twice* the SE. So:
SE <- (9.3 - -5.7) / (2*1.99)
should be the SE of the difference in the mean change between the two
groups. Dividing this by sqrt(1/n1 + 1/n2) should give you the SD of the
change scores (assuming homoscedasticity of the change variances in the two
groups), so:
SD <- SE / sqrt(1/30 + 1/36)
Hence:
1.8/SD
yields approximately 0.12. Sure you can apply the bias correction, but this
is hardly relevant here.
More importantly, this d-value standardizes the difference between the two
groups based on the (pooled) SD of the change scores. This is not comparable
to d-values that use the SD of a single time point for the standardization.
Best,
Wolfgang
-----Original Message-----
From: R-sig-meta-analysis [mailto:r-sig-meta-analysis-bounces at r-
On Behalf Of Tobias Saueressig
Sent: Monday, 17 August, 2020 12:03
To: r-sig-meta-analysis at r-project.org
Subject: [R-meta] Data Extraction
Hello,
I have a problem to extract data from one study.? I want to calculate
g.
I have the following information (2 groups):
Between-group change score from baseline to follow-up (9?months) is?1.8(-
5.7,9.3) (mean and 95%CI) and p-value 0.64
Sample size is n1 = 30; n2 = 36?(two group RCT).
Link:?https://linkinghub.elsevier.com/retrieve/pii/S1063458420309882?(TABLE
2 HOOS ADL)
I would do it the following way:
Calculate a SD for both group from the CI. _> SE = (Upper limit-lower
limit)/t-statistic (~2) => SD = SE/squ(1/n1?+ 1/n2)
Then g = d = MD/SD
g* = (1-3/(4*(n1+n2)-9) * g
e.g.
SE = (9.3+5.7)/1.99 = 7.54 => SD = 7.54/squ(1/30+1/36) = 7.54/0.25 = 30.16
g = 1.8/30.16 = 0.06
g* = 0.06 * (1-3/255) = 0.06 * 0.99 = 0.0594
Is that correct?
Best regards
Tobias