Message-ID: <c0f51304e02341cba22cb28b95e19271@UM-MAIL3214.unimaas.nl>
Date: 2020-06-08T10:41:41Z
From: Wolfgang Viechtbauer
Subject: [R-meta] Difference in Proportions Meta-Analysis
In-Reply-To: <CABE3OE29Wh_PPP4s8vuoEgA4S9mcm7dVWbqKrAsqScqOk-mHHg@mail.gmail.com>
Dear Nelly,
For two independent estimates, y1 and y2, with standard errors SE1 and SE2, the SE of their difference is:
SE[y1 - y2] = sqrt(SE1^2 + SE2^2)
Best,
Wolfgang
>-----Original Message-----
>From: R-sig-meta-analysis [mailto:r-sig-meta-analysis-bounces at r-project.org]
>On Behalf Of ne gic
>Sent: Monday, 08 June, 2020 12:37
>To: r-sig-meta-analysis at r-project.org
>Subject: [R-meta] Difference in Proportions Meta-Analysis
>
>Dear List,
>
>I aim to perform a meta-analysis and present a forest plot of the
>difference in proportions between two groups.
>
>For each group I have proportion and standard error (SE).
>
>It's straightforward to get the difference in the proportions, but am not
>sure how to handle the SEs, I presume I can't just subtract them. Is there
>a formula on how to handle SEs?
>
>Sincerely,
>nelly