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[R-meta] Question regarding Generalized Linear Mixed-effects Model for Meta-analysis

1/(np(1 ? p)) applies when you have a single proportion based on a binomial distribution, but this isn't what you have.

In your case, you have p ~ N(P, sigma^2 / n) (asymptotically) and then I just use the delta method (https://en.wikipedia.org/wiki/Delta_method) to get ln(p/(1-p)) ~ N(ln(P/(1-P)), 1/(P(1-P))^2 * sigma^2 / n). Then substitute p for P and s^2 for sigma^2.

1/(np(1 ? p)) is derived in the same way. For a 'binomial proportion', p ~ N(P, P(1-P)/n) asymptotically. Then ln(p/(1-p)) ~ N(ln(P/(1-P)), 1/(P(1-P))^2 * P(1-P)/n), which simplifies to 1/(nP(1-P) and then again substitute p for P.

Best,
Wolfgang

-----Original Message-----
From: Akifumi Yanagisawa [mailto:ayanagis at uwo.ca] 
Sent: Sunday, 07 January, 2018 23:41
To: Viechtbauer Wolfgang (SP)
Cc: r-sig-meta-analysis at r-project.org
Subject: Re: [R-meta] Question regarding Generalized Linear Mixed-effects Model for Meta-analysis

Thank you very much for clarifying my understanding, Wolfgang.

If you would not mind me asking one more question, could you let me know if there is any publication which I can cite how to calculate the sampling variance in this case: 1/(p*(1-p))^2 * s^2 / n)? I was able to figure out ?logit transformation?, and found the usual sample variance calculation for logit transformation for meta-analysis: 1/(np(1 ? p)); however, I could not find '1/(p*(1-p))^2 * s^2 / n)' by myself. 

Thank you so much,
Aki